二分查找,在经过: 34--https://leetcode-cn.com/problems/find-first-and-last-position-of-element-in-sorted-array/ 35--https://leetcode-cn.com/problems/search-insert-position/ 69--https://leetcode-cn.com/problems/sqrtx/ 367--https://leetcode-cn.com/problems/val…

一. 题目 1. Two Sum II Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the ta…

[java] /** * 递归分治算法学习之二维二分查找 * @author Sking 问题描述: 存在一个二维数组T[m][n],每一行元素从左到右递增, 每一列元素从上到下递增,现在需要查找元素X(必在二维 数组中)在数组中的位置,要求时间复杂度不超过m+n. */ package 递归分治; public class BinarySearchInArray { /** * 二维二分搜索的实现 * @param array 待查找的二维数组 * @param value  待查找的元素 *…

题意:给出数n, 代表有多少头牛, 这些牛的编号为1~n, 再给出含有n-1个数的序列, 每个序列的数 ai 代表前面还有多少头比 ai 编号要小的牛, 叫你根据上述信息还原出原始的牛的编号序列 分析:如果倒着看这个序列的话, 那序列的最后一个元素就能够确定一个编号.举个例子:如果序列的最后一个元素为0, 那就说明这头牛前面再也没有比它编号更小的牛了, 所以这头牛的编号肯定是最大的, 我们只要给它所在的编号加个标记, 然后继续根据倒数第二个.第三个……来依次确定便可还原整个序列, 这里可以使用树…

1057. Stack Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element). Now you…

public static void main(String[] args) throws Exception { /** * binarySearch(Object[], Object key) a: 要搜索的数组 key:要搜索的值 如果key在数组中,则返回搜索值的索引:否则返回-1或“-”(插入点).插入点是索引键将要插入数组的那一点,即第一个大于该键的元素的索引. 技巧: [1] 搜索值不是数组元素,且在数组范围内,从1开始计数,得“ - 插入点索引值”: [2] 搜索值是数组元素,从…

Estimation 时间限制(普通/Java):5000MS/15000MS     运行内存限制:65536KByte总提交: 6            测试通过: 1 描述 “There are too many numbers here!” your boss bellows. “How am I supposed to make sense of all of this? Pare it down! Estimate!”You are disappointed. It took a l…

一. 题目 1. Two SumTotal Accepted: 241484 Total Submissions: 1005339 Difficulty: Easy Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solutio…

Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…

题目传送门 题意:已知每个人的独一无二的身高以及排在他前面或者后面比他高的人数,问身高字典序最小的排法 分析:首先对身高从矮到高排序,那么可以知道每个人有多少人的身高比他高,那么取较小值(k[i], n - i - k[i]),若后者小于0则无解.然后可以理解为每个人前面要留出p + 1个位子给高个的人,可用线段树维护,s[rt] 表示当前线段还能空出的位子数.当然也能用树状数组+二分查找位子的方法. /**********************************************…