Leetcode ReorderList】的更多相关文章

/** * Source : https://oj.leetcode.com/problems/reorder-list/ * * Given a singly linked list L: L0→L1→-→Ln-1→Ln, * reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→- * * You must do this in-place without altering the nodes' values. * * For example, * Given {1,2,…
Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. (1)找出中间节点 (2)将后部分节点反转 (3)将前部分节点和后部分节点合并 #include…
Given a singly linked list L: L 0→L 1→-→L n-1→L n, reorder it to: L 0→L n →L 1→L n-1→L 2→L n-2→- You must do this in-place without altering the nodes' values. For example, Given{1,2,3,4}, reorder it to{1,4,2,3}. C++ /** * Definition for singly-linked…
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4}, reorder it to {1,4,2,3}. 这道链表重排序问题可以拆分为以下三个小问题: 1. 使用快慢指针来找到链表的中点,并将链表从中…
利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectangle-in-histo…
463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…
利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectangle-in-histo…
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Problem link: http://oj.leetcode.com/problems/reorder-list/ I think this problem should be a difficult problem, since it requries three classic algorithms on the single-linked list: Split a single-linked list into halves Reverse a single-linked list…
一.题目描述 Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 二.分析 1.暴力解法 这种解法所需的时间的时间复杂度比较高,为O(n2) 代码如下…