Pancake Sorting LT969】的更多相关文章

Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first k elements of A.  We want to perform zero or more pancake flips (doing them one after another in succession) to sort t…
Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first k elements of A.  We want to perform zero or more pancake flips (doing them one after another in succession) to sort t…
Difficulty: Medium Problem Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first k elements of A. We want to perform zero or more pancake flips (doing them one after anothe…
Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first kelements of A.  We want to perform zero or more pancake flips (doing them one after another in succession) to sort th…
Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first k elements of A.  We want to perform zero or more pancake flips (doing them one after another in succession) to sort t…
题目如下: Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the order of the first k elements of A.  We want to perform zero or more pancake flips (doing them one after another in succession) to…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 模拟法 日期 题目地址:https://leetcode.com/problems/pancake-sorting/ 题目描述 Given an array A, we can perform a pancake flip: We choose some positive integer k <= A.length, then reverse the…
每次找到当前最大数,转两下把最大数转到最右边.重复这个操作,直到都转完. 时间复杂度O(n**2) class Solution(object): def pancakeSort(self, A): """ :type A: List[int] :rtype: List[int] """ maxA,index,ret,size = 0,-1,[],len(A) if size==1: return [] for i, val in enumera…
这道题是LeetCode里的第969道题. 题目要求: 给定数组 A,我们可以对其进行煎饼翻转:我们选择一些正整数 k <= A.length,然后反转 A 的前 k 个元素的顺序.我们要执行零次或多次煎饼翻转(按顺序一次接一次地进行)以完成对数组 A的排序. 返回能使 A 排序的煎饼翻转操作所对应的 k 值序列.任何将数组排序且翻转次数在 10 * A.length范围内的有效答案都将被判断为正确. 示例 1: 输入:[3,2,4,1] 输出:[4,2,4,3] 解释: 我们执行 4 次煎饼翻…
问题:     星期五的晚上,一帮同事在希格玛大厦附近的“硬盘酒吧”多喝了几杯.程序员多喝了几杯之后谈什么呢?自然是算法问题.有个同事说:“我以前在餐馆打工,顾客经常点非常多的烙饼.店里的饼大小不一,我习惯在到达顾客饭桌前,把一摞饼按照大小次序摆好——小的在上面,大的在下面.由于我一只手托着盘子,只好用另一只手,一次抓住最上面的几块饼,把它们上下颠倒个个儿,反复几次之后,这摞烙饼就排好序了.我后来想,这实际上是个有趣的排序问题:假设有n块大小不一的烙饼,那最少要翻几次,才能达到最后大小有序的结果…