题目大意: 有n个国家要派代表开会,每个国家有两个代表可供选择. 有m对代表有仇,不能同时开会. 若每个国家只能派一个代表开会,问是否存在一种方案,使得每个国家都能正常参会? 如果有,输出字典序最小的一种. 思路: 2-SAT经典模型. 如果两个代表之间有仇,那么就给其中一个代表a连一条通向另一国家另一代表b的有向边,表示选a后一定要选b. 判定时就用Tarjan缩点,如果同一国家两个代表在同一个强连通分量中,那么说明两个代表必须同时参加或不参加,这是不合法的. 构造字典序最小的方案时,可以从小…

Peaceful Commission Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1948    Accepted Submission(s): 560 Problem Description The Public Peace Commission should be legislated in Parliament of Th…

HDU 1814 Peaceful Commission / HIT 1917 Peaceful Commission /CJOJ 1288 和平委员会(2-sat模板题) Description The Public Peace Commission should be legislated in Parliament of The Democratic Republic of Byteland according to The Very Important Law. Unfortunatel…

Peaceful Commission Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 79 Accepted Submission(s): 38   Problem Description The Public Peace Commission should be legislated in Parliament of The Democ…

hdu1814 Peaceful Commission 题意:2-sat裸题,打印字典序最小的 我写了三个 染色做法,正解 scc做法,不管字典序 scc做法,错误的字典序贪心 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <queue> using namespace std; const int N = 2e4+5,…

经典2sat裸题,dfs的2sat能够方便输出字典序最小的解... Peaceful Commission Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1578    Accepted Submission(s): 406 Problem Description The Public Peace Commission should…

Peaceful Commission Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2775    Accepted Submission(s): 865 Problem Description The Public Peace Commission should be legislated in Parliament of Th…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1814 Problem Description The Public Peace Commission should be legislated in Parliament of The Democratic Republic of Byteland according to The Very Important Law. Unfortunately one of the obstacles is t…

http://acm.hdu.edu.cn/showproblem.php?pid=1814 题意:n个2人组,编号分别为2n和2n+1,每个组选一个人出来,且给出m条关系(x,y)使得选了x就不能选y,问是否能从每个组选出1人.且输出字典序最小的答案.(n<=8000, m<=20000) #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #in…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1814 简单的2sat题. //STATUS:C++_AC_390MS_996KB #include <functional> #include <algorithm> #include <iostream> //#include <ext/rope> #include <fstream> #include <sstream> #inclu…