这题很智慧. VJ上4000多ms #include<cstdio> #include<algorithm> #include<queue> #include <stdio.h> #include <vector> using namespace std; int main() { int T,n,m,sum; ]; scanf("%d",&T); while(T--) { priority_queue<int…

priority_queue(优先队列)是一个拥有权值观念的queue,它允许加入新元素,删除旧元素,审视元素值等功能.由于这是一个queue,所以只允许在底端加入元素,并从顶端取出元素, 除此之外别无其它存取元素的途径. 缺省情况下priority_queue系列利用一个max_heap(最大堆)完成,后者是一个以vector表现的完全二叉树.Max_heap可以满足priority_queue所需要的“依权值高低自动递减排序”的特性.   priority_queue完全以底部容器为根据,再…

Given an unsorted array of integers, find the length of the longest consecutive elements sequence. For example,Given [100, 4, 200, 1, 3, 2],The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4. Your algorithm should run in…

适配器(Adaptor)是提供接口映射的模板类.适配器基于其他类来实现新的功能,成员函数可以被添加.隐藏,也可合并以得到新的功能. STL提供了三个容器适配器:queue.priority_queue.stack. 这些适配器都是包装了vector.list.deque中某个顺序容器的包装器.注意:适配器没有提供迭代器,也不能同时插入或删除多个元素.  本文地址:http://www.cnblogs.com/archimedes/p/cpp-adapter.html,转载请注明源地址. 队列(q…

Pro. 1 给定k个有序表,取其中前n小的数字.组成一个新表,求该表? 算法: 由于  a1[1] < a1[2] < a1[3] ... <a1[n] a2[1] < a2[2] < a2[3] ... < a2[n] ......... ak[1] < ak[2]<ak[3]...... < ak[n] 首先每个有序表的第一个元素入堆,然后最小元素出堆.该元素入新表L,相应线性表的下一个元素入堆. 例如:如果出堆得是a2[2],那么a2[3]入堆…

Sequence Time Limit: 6000MS Memory Limit: 65536K Total Submissions: 8277 Accepted: 2708 Description Given m sequences, each contains n non-negative integer. Now we may select one number from each sequence to form a sequence with m integers. It's clea…

Description Given m sequences, each contains n non-negative integer. Now we may select one number from each sequence to form a sequence with m integers. It's clear that we may get n ^ m this kind of sequences. Then we can calculate the sum of numbers…

/* * Copyright (c) 1994 * Hewlett-Packard Company * * Permission to use, copy, modify, distribute and sell this software * and its documentation for any purpose is hereby granted without fee, * provided that the above copyright notice appear in all c…

F - Sequence Time Limit:6000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Given m sequences, each contains n non-negative integer. Now we may select one number from each sequence to form a sequence with m int…

题目链接:http://poj.org/problem?id=2442 Time Limit: 6000MS Memory Limit: 65536K Description Given m sequences, each contains n non-negative integer. Now we may select one number from each sequence to form a sequence with m integers. It's clear that we ma…