Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ["nat","…

49. Group Anagrams Problem's Link ---------------------------------------------------------------------------- Mean: 给定一个由string类型构成的集合,让你按照每个字符串的单词构成集合来将这个集合分类. analyse: STL的运用. Time complexity: O(N) view code /** * ---------------------------------…

Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat",…

https://leetcode.com/problems/anagrams/ Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat&q…

Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ["nat","…

题目链接: https://leetcode.com/problems/anagrams/?tab=Description   Problem:给一个字符串数组,将其中的每个字符串进行分组,要求每个分组中的各个字符串所包含的字母都相同对字母的前后顺序没有要求!       使用 Map<String, List<String>> map 进行求解   给定的字符串数组为 String[] strs 1.当strs为空时返回new ArrayList<List<Strin…

lc49 Group Anagram 逻辑很简单,就是统计字母出现次数,然后将完全相同的字符串放入同一list 关键是怎么实现 统计的部分,可以通过将string排序,Arrays.sort(),或者像之前int[26]一样, 那么如何一次遍历,就能将相同字符串放入一个list呢? 这里用到了HashMap<String, List<String>>,String为key,用来判断排序过后的str是否相同,若是相同,直接原来的str加入List<String> 最后返回…

是之前的重排列字符串的延伸,判断是重排列后存到HashMap中进行分组 这种HashMap进行分组的方式很常用 public List<List<String>> groupAnagrams(String[] strs) { /* 其实重排列的那个题是有两种做法的,之前整理的是比较好的的一种字母哈希表的方法,还有一种方法 是把字符串排序,然后进行比较就行. 这个题正好就是用了排序的方法,排序后的字符串作为key,list作为value就行 一开始想用字母哈希表的方法,结果没做出来…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

LeetCode 49: 字母异位词分组 Group Anagrams 题目: 给定一个字符串数组,将字母异位词组合在一起.字母异位词指字母相同,但排列不同的字符串. Given an array of strings, group anagrams together. 示例: 输入: ["eat", "tea", "tan", "ate", "nat", "bat"], 输出: [ […

Question 49. Group Anagrams Solution 思路:维护一个map,key是输入数组中的字符串(根据字符排好序) Java实现: public List<List<String>> groupAnagrams(String[] strs) { Map<String, List<String>> map = new HashMap<>(); for (String str : strs) { String key = g…

一.题目说明 题目是49. Group Anagrams,给定一列字符串,求同源词(包含相同字母的此)的集合.题目难度是Medium. 二.我的做法 题目简单,就不多说,直接上代码: class Solution{ public: vector<vector<string>> groupAnagrams(vector<string>& strs) { vector<vector<string>> res; if(strs.size()&l…

一天一道LeetCode系列 (一)题目 Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"…

1. 原题链接 https://leetcode.com/problems/group-anagrams/description/ 2. 题目要求 给定一个字符串数组,将数组中包含相同字母的元素放在同一个列表,例如: 注意:所有的字母都是小写 3. 解题思路 首先对数组中的每个字符串按字母进行排序,这样含有相同字母的字符串排序后可以视作相等. 同时利用HasMap,将排序后的字符串作为key,排序前的作为value进行存储.最后返回HashMap的value即可. 4. 代码实现 import…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序+hash 日期 题目地址:https://leetcode.com/problems/anagrams/#/description 题目描述 Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", &quo…

题目: Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat&qu…

题目 Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat&quo…

思路:利用c++ stl的map来实现关键字匹配, 遍历strs容器类,对其中每一个string进行按字典序排序后,查找是否存在这样一个键,如不存在,存储该键,并将str[i]作为键映射的第一个元素:如存在,将str[i]添加到该键映射的vector<string>里. 最后用迭代器将map的映射即iter->second复制到题目要求返回的类型容器中. class Solution { public: vector<vector<string>> groupAn…

题目描述:给出一个由字符串组成的数组,把数组中字符串的组成字母相同的部分放在一个数组中,并把组合后的数组输出: 思路: 使用一个字典,键为数组中字符串排序后的部分,值为排序后相同的字符串组成的列表: 遍历数组完成后,返回字典的值就可以了. class Solution(object): def groupAnagrams(self, strs): """ :type strs: List[str] :rtype: List[List[str]] ""&qu…

题目描述 给定一个字符串数组,将字母异位词组合在一起.字母异位词指字母相同,但排列不同的字符串. 示例: 输入: ["eat", "tea", "tan", "ate", "nat", "bat"], 输出: [ ["ate","eat","tea"], ["nat","tan"], [&…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

49. 字母异位词分组 给定一个字符串数组,将字母异位词组合在一起.字母异位词指字母相同,但排列不同的字符串. 示例: 输入: ["eat", "tea", "tan", "ate", "nat", "bat"], 输出: [ ["ate","eat","tea"], ["nat","tan&quo…

Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat",…

Problem: Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -…

Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat",…

［抄题］: Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ["nat"…

There are n people whose IDs go from 0 to n - 1 and each person belongs exactly to one group. Given the array groupSizes of length n telling the group size each person belongs to, return the groups there are and the people's IDs each group includes.…

原题地址 Anagram:变位词.两个单词是变位词关系的条件是:组成单词的字符相同,只是顺序不同 第一次看这道题看了半天没明白要干嘛,丫就不能给个样例输入输出么..后来还是看网上其他人的总结知道是怎么回事. 通常的做法是:把字符串内的字符排序,这样,凡是变位词都会变成相同的单词.用map记录这样的单词出现了几个,如果超过1个,则加入结果集中. 代码: vector<string> anagrams(vector<string> &strs) { vector<stri…

Given an array of strings, return all groups of strings that are anagrams. Note: All inputs will be in lower-case. 题目: 给一组字符串,返回所有满足Anagrams(回文构词法)的字符串: Anagrams是指由颠倒字母顺序组成的单词,比如“dormitory”颠倒字母顺序会变成“dirty room”,“tea”会变成“eat”. 回文构词法有一个特点:单词里的字母的种类和数目没…

Description: Count the number of prime numbers less than a non-negative number, n. 推断一个数是否是质数主要有下面几种方法: 1)直接用该数除于全部小于它的数(非0.1),假设均不能被它整除,则其是质数. 2)除以小于它一半的数.由于大于其一半必然是无法整除.假设均不能被它整除.则其是质数: 3)除以小于sqrt(a)的数,原因例如以下: 除了sqrt(a)之外,其它的两数乘积为a的,一定是比个比sqrt(a)小,…