二分. 统计过程如下图: 先统计红线上的个数,然后统计绿线上的个数,然后统计咖啡色线上的个数......一个一个往下统计就可以了. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #incl…

Archer Time Limit: 2000ms Memory Limit: 262144KB This problem will be judged on CodeForces. Original ID: 312B64-bit integer IO format: %I64d      Java class name: (Any)   SmallR is an archer. SmallR is taking a match of archer with Zanoes. They try t…

The Goddess Of The Moon Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1487    Accepted Submission(s): 650 Problem Description Chang’e (嫦娥) is a well-known character in Chinese ancient mytholog…

The Goddess Of The Moon Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 589    Accepted Submission(s): 251 Problem Description Chang’e (嫦娥) is a well-known character in Chinese ancient mythology…

The Goddess Of The Moon Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 943    Accepted Submission(s): 426 Problem Description Chang’e (嫦娥) is a well-known character in Chinese ancient mythology…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=5318 The Goddess Of The Moon Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 438    Accepted Submission(s): 150 Problem Description Chang'e (嫦娥) is…

B. Archer Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/312/problem/B Description SmallR is an archer. SmallR is taking a match of archer with Zanoes. They try to shoot in the target in turns, and SmallR shoots first. The…

A. Warrior and Archer Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/594/problem/A Description In the official contest this problem has a different statement, for which jury's solution was working incorrectly, and for this…

题 SmallR is an archer. SmallR is taking a match of archer with Zanoes. They try to shoot in the target in turns, and SmallR shoots first. The probability of shooting the target each time is  for SmallR while  for Zanoes. The one who shoots in the tar…

595C - Warrior and Archer 思路:设最后答案的区间为[l,r],那么r-l等于n/2,因为在(l,r)中的点都是其中一个人挖掉的,[0,l)和(r,n]中的点是另一个人挖掉的,两者相等. 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mp make_pair #define pi acos(-1.0) #define p…