POJ 2593&&2479:Max Sequence】的更多相关文章

Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16329   Accepted: 6848 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S.  Input The input will consist of several test cases. F…
d(A) = max{sum(a[s1]..a[t1]) + sum(a[s2]..a[t2]) | 1<=s1<=t1<s2<=t2<=n} 即求两个子序列和的和的最大值. 为单个区间子序列和的最大值的变形. 左边的从左向右扫描,而右边的从右向左扫描即可. #include<cstdio> #include<algorithm> using namespace std; const int MAXN=50000+10; int left[MAXN],…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 17678   Accepted: 7401 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N).  You should output S.  Input The input will consist of several test cases.…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 18511   Accepted: 7743 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S.  Input The input will consist of several test cases. F…
Matlab中max函数在矩阵中求函数大小的实例如下: C = max(A)返回一个数组各不同维中的最大元素.如果A是一个向量,max(A)返回A中的最大元素.如果A是一个矩阵,max(A)将A的每一列作为一个向量,返回一行向量包含了每一列的最大元素.如果A是多为数组,max(A) treats the values along the first non-singleton dimension as vectors, returning the maximum value of each ve…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16850   Accepted: 7054 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S. Input The input will consist of several test cases. Fo…
题目链接:Max Sum Plus Plus Plus 题意:在n个数中取m段数使得这m段数之和最大,段与段之间不能重叠 分析:见代码 //dp[i][j]表示前i个数取了j段的最大值 //状态转移:dp[i][j]=max(dp[k][j-1]+(sum[k+l[j]-sum[k]或者sum[i]-sum[i-l[j]) (0<=k<=i-l[j]) // 这种做法是O(n^2)的 //如果改成O(n)的呢? //需要加一个数组max_dp[i][j]表示前i个数取j段的dp最大值 //如果…
[九度OJ]题目1442:A sequence of numbers 解题报告 标签(空格分隔): 九度OJ 原题地址:http://ac.jobdu.com/problem.php?pid=1442 题目描述: Xinlv wrote some sequences on the paper a long time ago, they might be arithmetic or geometric sequences. The numbers are not very clear now, a…
题目链接:http://poj.org/problem?id=2593 思路分析:该问题为求给定由N个整数组成的序列,要求确定序列A的2个不相交子段,使这m个子段的最大连续子段和的和最大. 该问题与poj 2479相同,解法也一样: 代码如下: #include <cstdio> #include <iostream> using namespace std; + ; int arr[MAX_N], dp_s[MAX_N], dp_r[MAX_N]; int arr_num; in…
Number Sequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 36013   Accepted: 10409 Description A single positive integer i is given. Write a program to find the digit located in the position i in the sequence of number groups S1S2..…