dmesgcat /proc/interrupts cat /proc/meminfocat /proc/cpuinfo top bootz 0x10000000 0x12000000 0x11000000 fsck mkdir -p /mnt/emmc1mkdir -p /mnt/emmc2 mount /dev/mmcblk0p1 /mnt/emmc1/mount /dev/mmcblk0p2 /mnt/emmc2/mount -t nfs -o nolock,nfsvers=3,vers=…

前面学习了从系统级到门级的低功耗设计,现在简单地了解了一下物理级设计.由于物理级的低功耗设计与后端有关了,这里就不详细学习了.这里主要是学习了一些基本原则,在物理级,进行低功耗设计的基本原则是:   ·对于设计中翻转活动很频繁的节点,采用低电容的金属层进行布线; ·使高翻转率的节点尽可能地短;  ·对于高负载的节点与总线,采用低电容的金属层; ·对于特别宽的器件,采用特殊的版图技术,以得到更小的漏极结电容.  ·在有些布局布线工具中,可以将功耗作为优化目标来生成时钟树. 低功耗设计入门的学习到这…

A continued fraction of height n is a fraction of form . You are given two rational numbers, one is represented as  and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-se…

u-boot 加载 kernel 的流程分析. image重要结构体头文件 // include/image.h * * Legacy and FIT format headers used by do_bootm() and do_bootm_<os>() * routines. */ // 这是正bootm 头部结构体 typedef struct bootm_headers { /* * Legacy os image header, if it is a multi component…

B. Continued Fractions time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A continued fraction of height n is a fraction of form . You are given two rational numbers, one is represented as  a…

任意门:http://codeforces.com/gym/100641/attachments Con + tin/(ued + Frac/tions) Time Limit: 3000/1000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 217     Accepted Submission(s): 27 Description The (simple) contin…

先上题目: Continued Fraction Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 332    Accepted Submission(s): 106 Problem Description Dumbear loves numbers very much.One day Dumbear found that each n…

1638: Continued Fraction Time Limit: 1 Sec  Memory Limit: 128 MB Description Input Output Sample Input 4 3 5 1 1 2 5 2 2 Sample Output 11 0 5 30 4 6 1 27 HINT   Source 解题:主要任务是把任一一个分数化成连分式.   方法就是分子分母同时不断的除以分子,直到分子为0.   至于加,减,乘,除都是先算出分数,然后把分数化成连分数..…

1.什么是Java虚拟机?为什么Java被称作是“平台无关的编程语言”?答:Java虚拟机是一个可以执行Java字节码的虚拟机进程.Java源文件被编译成能被Java虚拟机执行的字节码文件.Java被设计成允许应用程序可以运行在任意的平台,而不需要程序员为每一个平台单独重写或者是重新编译.Java虚拟机让这个变为可能,因为它知道底层硬件平台的指令长度和其他特性. 2.JDK和JRE的区别是什么?答:Java运行时环境(JRE)是将要执行Java程序的Java虚拟机.它同时也包含了执行applet…

The more I get to install/upgrade to CRM 2011 in different environment the more I come across different issues and fortunately there are workarounds to it. So here are some additional items found since the last post on this subject. A Microsoft Dynam…