Gopher II Time Limit: 2000MS Memory Limit: 65536K Description The gopher family, having averted the canine threat, must face a new predator. The are n gophers and m gopher holes, each at distinct (x, y) coordinates. A hawk arrives and if a gopher doe…

Gopher II Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9005   Accepted: 3724 Description The gopher family, having averted the canine threat, must face a new predator. The are n gophers and m gopher holes, each at distinct (x, y) coor…

题目链接: http://poj.org/problem? id=2536 题目大意: 有N仅仅鼹鼠和M个洞穴,假设鼹鼠在S秒内不可以跑到洞穴,就会被老鹰捉住吃掉. 鼹鼠跑的速度为V米/秒. 已知一个洞穴仅仅能容纳一仅仅鼹鼠.给你鼹鼠和洞穴的坐标,那么问题来了:问最少有多少仅仅鼹鼠被老鹰捉住 吃掉. 思路: 建立一个二分图,一边为鼹鼠,还有一边为洞穴枚举求出每仅仅鼹鼠到各个洞穴的距离,把可以在S秒内跑到该 洞穴(距离<=S*V)的进行连边.建好图后用匈牙利算法求出最多有多少仅仅鼹鼠可以幸免于难(…

题目传送门 /* 匈牙利算法:这题比UVA_670简单,注意是要被吃的鼠的最少个数,套模板 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <vector> using namespace std; ; const int INF = 0x3f3f3f3f; struct P { double x, y; }a[MAXN]…

匈牙利算法 var i,j,k,l,n,m,v,mm,ans:longint; a:..,..]of longint; p,f:..]of longint; function xyl(x,y:longint):boolean; var i,j,k,l:longint; begin if f[x]=y then exit(false); f[x]:=y; to m do ))or(xyl(p[i],y)))then begin p[i]:=x; exit(true); end; exit(fals…

Marriage Match II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1608    Accepted Submission(s): 566 Problem Description Presumably, you all have known the question of stable marriage match. A…

Gopher II Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6675   Accepted: 2732 Description The gopher family, having averted the canine threat, must face a new predator. The are n gophers and m gopher holes, each at distinct (x, y) coor…

//匈牙利算法-DFS //求最小点覆盖集 == 求最大匹配 //Time:0Ms Memory:208K #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; #define MAX 105 #define INF 0x3f3f3f3f int n,m,k; int gp[MAX][MAX]; bool sx[MAX],s…

匈牙利算法是由匈牙利数学家Edmonds于1965年提出,因而得名.匈牙利算法是基于Hall定理中充分性证明的思想,它是部图匹配最常见的算法,该算法的核心就是寻找增广路径,它是一种用增广路径求二分图最大匹配的算法. -------等等,看得头大?那么请看下面的版本: 通过数代人的努力,你终于赶上了剩男剩女的大潮,假设你是一位光荣的新世纪媒人,在你的手上有N个剩男,M个剩女,每个人都可能对多名异性有好感(-_-||暂时不考虑特殊的性取向),如果一对男女互有好感,那么你就可以把这一对撮合在一起,现在…

Strategic Game Bob enjoys playing computer games, especially strategic games, but sometimes he cannot find the solution fast enough and then he is very sad. Now he has the following problem. He must defend a medieval city, the roads of which form a t…