Coins Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 34814   Accepted: 11828 Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some…

Vjudge传送门 $Sol$ 首先发现这是一个多重背包,所以可以用多重背包的一般解法(直接拆分法,二进制拆分法...) 但事实是会TLE,只能另寻出路 本题仅关注“可行性”(面值能否拼成)而不是“最优性”,这是一个特殊之处. 从这里找优化 在“最优性”的问题中,$f[j]$从$f[j]$或$f[j-a[i]]$中转移而来:而在这样的“可行性”问题中,其实只要$f[j]$可行,我们就可以不用考虑$f[j-a[i]$了,也可以反过来说. 于是我们可以考虑一种贪心策略,设$used[j]$表示$f[…

Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coins.He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact pri…

题目:http://poj.org/problem?id=1742 贪心地想,1.如果一种面值已经可以被组成,则不再对它更新: 2.对于同一种面值的硬币,尽量用较少硬币(一个)更新,使后面可以用更多此面值硬币. 代码如下: #include<iostream> #include<cstdio> #include<cstring> using namespace std; ],c[],m,used[],ans; ]; int main() { ) { ; memset(f…

Cash Machine Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 32971   Accepted: 11950 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The m…

POJ 3260 The Fewest Coins(多重背包+全然背包) http://poj.org/problem?id=3260 题意: John要去买价值为m的商品. 如今的货币系统有n种货币,相应面值为val[1],val[2]-val[n]. 然后他身上每种货币有num[i]个. John必须付给售货员>=m的金钱, 然后售货员会用最少的货币数量找钱给John. 问你John的交易过程中, 他给售货员的货币数目+售货员找钱给他的货币数目 的和最小值是多少? 分析: 本题与POJ 12…

Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One day Hibix opened purse and found there were some coins. He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact price(witho…

The Fewest Coins DescriptionFarmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he uses to pay plus…

Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coins.He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact pri…

Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12330    Accepted Submission(s): 4922 Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One…

这道题是典型的多重背包的题目,也是最基础的多重背包的题目 题目大意:给定n和m, 其中n为有多少中钱币, m为背包的容量,让你求出在1 - m 之间有多少种价钱的组合,由于这道题价值和重量相等,所以就是dp[i] = i, 其中dp[i]表示当前背包容量为i 的时候背包能装的价值. 题目思路: 模板 二进制优化 话说那个二进制真的很奇妙,只需要2的1次方 到 2的k-1次方, 到最后在加上一项当前项的个数 - 2 的k次方 + 1,也就是这些系数分别为1; 2; 22 .....2k-1;Mi…

意甲冠军:你有N种硬币,每个价格值A[i],每个号码C[i],要求. 在不超过M如果是,我们用这些硬币,有多少种付款的情况下,.那是,:1,2,3,4,5,....,M这么多的情况下,,你可以用你的硬币不找零,种情况. 比如: 你有一种硬币,价值2.个数2,那么 你是不能付款 3元的..你仅仅能付款2,或者4元.. OK,题意差点儿相同就是这样啦. 那么这里有两种方式! 分析: 那么这里我们能够用多重背包来解决,我们把价值和重量看成一样的w[i] = A[i]:用M作为背包. 那么dp 过后.我…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=2844 思路:多重背包 , dp[i] ,容量为i的背包最多能凑到多少容量,如果dp[i] = i,那么代表这个数能凑出来,ans+1: 实现代码: #include<bits/stdc++.h> using namespace std; ; int lis[M],dp[M],a[M],c[M]; int main() { int n,m,idx; while(cin>>n>>m…

题意 给n个币的价值和其数量,问能组合成\(1-m\)中多少个不同的值. 分析 对\(c[i]*a[i]>=m\)的币,相当于完全背包:\(c[i]*a[i]<m\)的币则是多重背包,考虑用二进制优化解决.最后扫一遍\(dp[i]\)统计答案. import java.util.*; import java.math.*; public class Main{ static int MAXN = 100005; static int []dp = new int[MAXN]; static i…

Dividing Time Limit: 1000MS Memory Limit: 10000K Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. This would be easy if all the marbles had…

Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One day Hibix opened purse and found there were some coins. He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact price(witho…

Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coins.He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact pri…

Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8999    Accepted Submission(s): 3623 Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One…

Coins                                                                             Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silve…

Coins Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 28448   Accepted: 9645 Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some…

题目意思:给出你n种硬币的面额和数量,询问它能够组合成1~m元中的几种情况. 这题如果直接按照完全背包来写的话,会因为每一种硬币的数目1 ≤ Ci ≤ 1000而超时,所以这里需要运用二进制优化来解决问题. 二进制优化和快速幂的思路是一样的. 例如:面值为1的硬币有20枚,如果完全背包的话就需要20次状态转移. 运用二进制优化后,就变成了 面值为1的硬币1枚.面值为2的硬币1枚.面值为4的硬币1枚.面值为8的硬币1枚,最后多出的5个,就直接作为面值为5的硬币一枚,加入新的数组中.之前的20次转移…

题目链接:https://cn.vjudge.net/problem/HDU-2844 题意 给你一些不同价值和一定数量n的硬币. 求用这些硬币可以组合成价值在[1 , m]之间的有多少. 思路 多重背包问题,看了一眼数据范围,用二进制优化一下物品数量即可. 提交过程 AC 代码 #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int maxn=10…

Dividing Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 68769   Accepted: 17955 Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbl…

题意:有n种面额的硬币.面额.个数分别为A_i.C_i,求最多能搭配出几种不超过m的金额? 思路:dp[j]就是总数为j的价值是否已经有了这种方法,如果现在没有,那么我们就一个个硬币去尝试直到有,这种价值方法有了的话,那么就是总方法数加1.多重背包可行性问题 传统多重背包三重循环会超时,因为只考虑是否可行,没有考虑剩余面额数量的因素. o(n*v)方法 #include <iostream> #include <cstdio> #include <string.h> #…

http://poj.org/problem? id=1742 Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coins.He decided to buy a very nice watch in a nearby shop…

http://poj.org/problem?id=3260   Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he…

Coins  HDU 2844 不能用最基础的多重背包模板:会超时的!!! 之后看了二进制优化了的多重背包. 就是把多重转变成01背包: 具体思路见:http://www.cnblogs.com/tt123/p/3280521.html #include<iostream> #include<algorithm> #include<stdio.h> #include<string.h> using namespace std; ],a1[],a[],b[];…

Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10632    Accepted Submission(s): 4230 Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One…

Coins Time Limit: 3000MS Memory Limit: 30000K Total Submissions: 25827 Accepted: 8741 Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coin…

Problem Description Whuacmers use coins.They have coins of value A1,A2,A3...An Silverland dollar. One day Hibix opened purse and found there were some coins. He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact price(witho…