HDU 5418 Victor and World Time Limit:2000MS     Memory Limit:131072KB     64bit IO Format:%I64d & %I64u After trying hard for many years, Victor has finally received a pilot license. To have a celebration, he intends to buy himself an airplane and fl…
问题 The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can afford to hire only one driver to do the deliveries. He will wait for 1 or more (up to 10) orders to be processed…
胜利大逃亡(续) Problem Description Ignatius再次被魔王抓走了(搞不懂他咋这么讨魔王喜欢)…… 这次魔王汲取了上次的教训,把Ignatius关在一个n*m的地牢里,并在地牢的某些地方安装了带锁的门,钥匙藏在地牢另外的某些地方.刚开始Ignatius被关在(sx,sy)的位置,离开地牢的门在(ex,ey)的位置.Ignatius每分钟只能从一个坐标走到相邻四个坐标中的其中一个.魔王每t分钟回地牢视察一次,若发现Ignatius不在原位置便把他拎回去.经过若干次的尝试,I…
Description #define xhxj (Xin Hang senior sister(学姐)) If you do not know xhxj, then carefully reading the entire description is very important. As the strongest fighting force in UESTC, xhxj grew up in Jintang, a border town of Chengdu. Like many god…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1074 题目大意:学生要完成各科作业, 给出各科老师给出交作业的期限和学生完成该科所需时间, 如果逾期一天则扣掉一单位学分, 要你求出完成所有作业而被扣最小的学分, 并将完成作业的顺序输出. Sample Input 2 3 Computer 3 3 English 20 1 Math 3 2 3 Computer 3 3 English 6 3 Math 6 3   Sample Output 2…
XHXJ's LIS Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2265    Accepted Submission(s): 927 Problem Description #define xhxj (Xin Hang senior sister(学姐)) If you do not know xhxj, then careful…
Victor and World Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 891    Accepted Submission(s): 399 Problem Description After trying hard for many years, Victor has finally received a pilot li…
题目链接: hdu: http://acm.hdu.edu.cn/showproblem.php?pid=5418 bestcoder(中文): http://bestcoder.hdu.edu.cn/contests/contest_chineseproblem.php?cid=619&pid=1002 Victor and World  Accepts: 99  Submissions: 644  Time Limit: 4000/2000 MS (Java/Others)  Memory…
Victor and World Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others) Total Submission(s): 1463    Accepted Submission(s): 682 Problem Description After trying hard for many years, Victor has finally received a pilot…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5418 题目大意:有n个结点m条边(有边权)组成的一张连通图(n <16, m<100000).求从第一个点出发,经过每个点至少一次后回到原点的最小路径边权和. 分析:发现我还真是菜. n<16,很明显的状态压缩标记,先将所有点的编号减去1,使其从0开始编号.dp[i][j]表示从0号点出发,当前状态为i (二进制位为1表示对应点已走过,否则没走过), 当前位置为 j,  回到原点的最小代价,…