For a string of n bits x1, x2, x3,…, xn, the adjacent bit count of the string (AdjBC(x)) is given by x1 ∗ x2 + x2 ∗ x3 + x3 ∗ x4 + . . . + xn−1 ∗ xn which counts the number of times a 1 bit is adjacent to another 1 bit. For example: AdjBC(011101101)…
Adjacent Bit Counts 4557 Adjacent Bit CountsFor a string of n bits x 1 , x 2 , x 3 ,..., x n , the adjacent bit count of the string (AdjBC(x)) is given byx 1 ∗ x 2 + x 2 ∗ x 3 + x 3 ∗ x 4 + . . . + x n−1 ∗ x nwhich counts the number of times a 1 bit…
Adjacent Bit Counts Time Limit: 1000ms Memory Limit: 65536KB 64-bit integer IO format: %lld Java class name: Main Prev Submit Status Statistics Discuss Next Type: None None Graph Theory 2-SAT Articulation/Bridge/Biconnected Compo…
Adjacent Bit Counts Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 599 Accepted: 502 Description For a string of n bits x1, x2, x3, …, xn, the adjacent bit count of the string (AdjBC(x)) is given by x1*x2 + x2*x3 + x3*x4 + … + xn-1*xn…
描述 For a string of n bits x1, x2, x3, …, xn, the adjacent bit count of the string is given by fun(x) = x1*x2 + x2*x3 + x3*x 4 + … + xn-1*x n which counts the number of times a 1 bit is adjacent to another 1 bit. For example: Fun(011101101) = 3…
C: 最舒适的路线 (并查集) #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; #define INF 20000000 struct point { int x, y, v; }; point node[]; ]; bool cmp(point a, point b) { return a.v < b.v;/…
F - Palindrometer Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submit Status Practice UVALive 4868 Description While driving the other day, John looked down at his odometer, and it read 100000. John was pretty excited about…
