题目链接: A. Complicated GCD time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output   Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that bot…

[题目链接] 点击打开链接 [算法] gcd(a,a+1) = 1 所以当a = b时,答案为a,否则为1 [代码] #include<bits/stdc++.h> using namespace std; string a,b; int main() { cin >> a >> b; if (a == b) cout<< a << endl; << endl; ; }…

题目链接: B. Modulo Sum time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of numbers a1, a2, ..., an, and a number m. Check if it is possible to choose a non-empty subse…

A.Beru-taxi 水题:有一个人站在(sx,sy)的位置,有n辆出租车,正向这个人匀速赶来,每个出租车的位置是(xi, yi) 速度是 Vi;求人最少需要等的时间: 单间循环即可: #include<iostream> #include<algorithm> #include<string.h> #include<stdio.h> #include<math.h> #include<vector> using namespace…

这题一眼看就是水题,map随便计 然后我之所以发这个题解,是因为我用了log2()这个函数判断在哪一层 我只能说我真是太傻逼了,这个函数以前听人说有精度问题,还慢,为了图快用的,没想到被坑惨了,以后尽量不用 #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <iostream> #include <algorithm> #…

题意:给定 n 和 k,然后是 n 个数,表示1-k的一个值,问你修改最少的数,使得所有的1-k的数目都等于n/k. 析:水题,只要用每个数减去n/k,然后取模,加起来除以2,就ok了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cma…

Problem G.Giant ScreenTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86821#problem/G Description You are working in Advanced Computer Monitors (ACM), Inc. The company is building and selling giant c…

题目链接: A. King Moves 题意: 给出king的位置,问有几个可移动的位置; 思路: 水题,没有思路; AC代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include &l…

题目链接: A. Round House time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entra…

B. BerSU Ball time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are al…

题目链接: A. Maximum Increase time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given array consisting of n integers. Your task is to find the maximum length of an increasing subarray of…

C. CinderellaTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100685/problem/C Description Cinderella is given a task by her Stepmother before she is allowed to go to the Ball. There are N (1 ≤ N ≤ 1000) bottles with water in th…

题目链接:http://codeforces.com/problemset/problem/44/E 题意: 给一个字符串,让你分割成 $k$ 行,每行的字母数在 $[a,b]$ 之间. 题解: 这是1500difficulty的DP题? AC代码: #include<bits/stdc++.h> using namespace std; int k,a,b; string s; int main() { cin>>k>>a>>b; cin>>s…

题意:给定两个相同长度的字符串,让你找出一个字符串,字典序在两都之间. 析:这个题当时WA了好多次,后来才发现是这么水,我们只要把 s 串加上,然后和算数一样,该进位进位,然后再和 t 比较就行. 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <vector> #include <set> #include <cstring> #in…

大概题意就是求\(1 \le i,j \le n\)的\(gcd(i,j) = 1\)的个数+2(对于0的特判) 正解应该是欧拉函数或者高逼格的莫比乌斯反演 但数据实在太水直接打表算了 /*H E A D*/ bool GCD[1002][1002]; inline int gcd(int a,int b){return b?gcd(b,a%b):a;} int main(){ rep(i,1,1000) rep(j,1,1000) GCD[i][j]=bool(gcd(i,j)==1); in…

原题链接:http://codeforces.com/gym/100431/attachments/download/2421/20092010-winter-petrozavodsk-camp-andrew-stankevich-contest-37-asc-37-en.pdf 题意 神奇的电路可以通过比较器来实现冒泡. 题解 倒着往回考虑,搞搞就好. 代码 #include<iostream> #include<cstdio> #include<cstring> #…

题意:sb要从a到b,然后要乘坐飞机,只有两家有飞机,如果乘坐同一家的,就免费,如果不是就收到abs(j-i) 的费用,问你最少花费是多少. 析:直接考虑a和b是不是同一家的,如果是,花费为0,如果不是,花费为1.这样才是最少的. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdli…

题目链接:http://codeforces.com/problemset/problem/710/A 题目大意:在一个棋盘中给出一个位置,判断该位置周围8个点还有几个点可以摆放棋子. AC代码解释解法: #include<bits/stdc++.h> using namespace std; int main() { char c; int x,y; while(~scanf("%c%d",&c,&x)) { getchar(); y=c-; &&…

题意:给定一个字符串,让你把它的一个子串字符都减1,使得总字符串字典序最小. 析:由于这个题是必须要有一个字串,所以你就要注意这个只有一个字符a的情况,其他的就从开始减 1,如果碰到a了就不减了,如果到最后一位了还没开始减, 就减最后一位. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <c…

B. Island Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100114 Description On February 30th this year astronauts from the International Space Station flew over the Pacific Ocean and took a picture, on which was discovered a pr…

题目链接:https://codeforces.com/contest/1090/problem/A A conglomerate consists of n companies. To make managing easier, their owners have decided to merge all companies into one. By law, it is only possible to merge two companies, so the owners plan to s…

B. s-palindrome 题目连接: http://www.codeforces.com/contest/691/problem/B Description Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the…

C. History time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Polycarpus likes studying at school a lot and he is always diligent about his homework. Polycarpus has never had any problems wit…

题目链接: A. Co-prime Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given an array of n elements, you must make it a co-prime array in as few moves as possible. In each move you…

题目链接: A. Pouring Rain time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you h…

题意:给定一个序列,让你用最少的操作把它变成交替的,操作有两种,任意交换两种,再就是把一种变成另一种. 析:贪心,策略是分别从br开始和rb开始然后取最优,先交换,交换是最优的,不行再变色. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <c…

题意:给定一个序列表示飞机要向哪个方向飞一个单位,让你改最少的方向,使得回到原点. 析:一个很简单的题,把最后的位置记录一下,然后要改的就是横坐标和纵坐标绝对值之和的一半. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath>…

题目链接: http://codeforces.com/contest/659/problem/A 题意: 一个圈,按逆时针编号,给定起点,方向和步数,问终点在几号? 分析: 很简单的模拟...注意答案为0的时候应该输出n... 代码: #include<iostream> using namespace std; int main (void) { int n, a, b;cin>>n>>a>>b; b = (b - 1) %n + 1; int k =…

题意:给定一行字符串,让你统计在括号外最长的单词和在括号内的单词数. 析:直接模拟,注意一下在左右括号的时候有没有单词.碰到下划线或者括号表示单词结束了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include…

题意:给定一行字符串,让你输出字符‘B'连续出现的次数. 析:直接扫一下就OK了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstrin…