[Leetcode 78]求子集 Subset】的更多相关文章

[题目] Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. 求子集,无重复数 [思路] 1.有回溯法模板 2.将tmp加入进ans.tmp用来存放第i个元素的子集.回溯产生第i个元素与其后[i+1,len]元素产生的子集(i-1前已经产生过,不重复遍历).因第i…
LeetCode 78 网上已经又很多解这题的博客了,在这只是我自己的解题思路和自己的代码: 先贴上原题: 我的思路: 我做题的喜欢在本子或别处做写几个示例,以此来总结规律:下图就是我从空数组到数组长度为4的示例 在写这些例子的时候,我发现,数组中每增加一个元素,其结果就是前一个结果集(数组长度为n-1的结果)的基础上加上新增的这个元素得到的结果集再加前一个结果集:可能叙述的不清楚我把上面的图片规整下把 例: 规律差不多讲完了,如果还是不清楚请留言,我们一对一解释,现在来贴代码 结果:…
Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If nums = [1,2,3], a solution is: [ [3], [1], [2], [1,2…
[题目] Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. [思路] 注意sort,使得判断临接元素是否相邻. 与leetcode78类似,多了一个重复数判断条件 if(i>flag&&nums…
[题目] Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers. Note: All numbers will be positive integers. The solution set must not…
Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1…
A - A Time Limit:0MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice SCU 4424 Description Time Limit: 1000ms Description Given N distinct elements, how many permutations we can get from all the possible subset of the eleme…
题目:矩阵置0 难度:Easy 题目内容:   Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. 翻译: 给定一组不同的整数,nums,返回所有可能的子集(包括空集和自身). 注意:解决方案集不能包含重复的子集. Example: Input: nums = […
题目链接:https://leetcode.com/problems/subsets/#/description   给出一个数组,数组中的元素各不相同,找到该集合的所有子集(包括空集和本身) 举例说明: int []nums={1,2,3}  返回结果如下: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] 使用回溯法解决上述问题.   相当于对一棵树的深度遍历操作.    上述的输出结果还是有些规律的,也就是按照子集的元素个数来进行分解,…