Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 214    Accepted Submission(s): 89 Problem Description Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.For n…

Bazinga Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5510 Description Ladies and gentlemen, please sit up straight. Don't tilt your head. I'm serious.For n given strings S1,S2,⋯,Sn, labelled from 1 to n, you…

Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2287    Accepted Submission(s): 713 Problem Description Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.For…

Bazinga HDU 5510 Bazinga(双指针) 题链 解法:对于串i来说,如果串i是不符合的,那么代表串i之前的字符串都是i的子串,那么我们求一个新的i(定义为ti),如果i是ti 的子串,那么串i之前的字符串都没必要再匹配了,如果不是,ti就是符合要求的答案之一 #include <cstdio> #include <iostream> #include <cstring> using namespace std; const int N=2005; ch…

http://acm.hdu.edu.cn/showproblem.php?pid=5510 Bazinga Problem Description   Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.For n given strings S1,S2,⋯,Sn, labelled from 1 to n, you should find the largest i (1≤i≤n) su…

Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2078    Accepted Submission(s): 642 Problem Description  to n, you should find the largest i (1≤i≤n) such that there exists an integer j (…

Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 593    Accepted Submission(s): 241 Problem Description Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.For …

Bazinga means Bazinga https://www.dictionary.com/e/slang/bazinga/ refs xgqfrms 2012-2020 www.cnblogs.com 发布文章使用:只允许注册用户才可以访问!…

题目:传送门. 题意:t 组数据,每组 n 个串,对于第 i 个串如果存在 1 到 i-1 中的某个串不是 i 的子串,那么这个第 i 个串符合题意,求 i 的最大值. 题解:KMP,AC自动机也可以,直接匹配就行.注意如果串 j 是j+1的子串,那么对于j+2来说只需要匹配j+1是不是他的子串即可,因为比匹配 j 更容易符合题意.用cin会超时,要用scanf. #include <iostream> #include <cstdio> #include <cmath>…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5510 普通集合会tle,换高贵的并查集. #include <algorithm> #include <iostream> #include <iomanip> #include <cstring> #include <climits> #include <complex> #include <fstream> #includ…