LeetCode 136. Single Number(只出现一次的数字)…

题目描述: 中文: 给定一个非空整数数组,除了某个元素只出现一次以外,其余每个元素均出现两次.找出那个只出现了一次的元素. 说明: 你的算法应该具有线性时间复杂度. 你可以不使用额外空间来实现吗? 英文: Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear ru…

题目描述: 中文: 给定一个非空整数数组,除了某个元素只出现一次以外,其余每个元素均出现了三次.找出那个只出现了一次的元素. 说明: 你的算法应该具有线性时间复杂度. 你可以不使用额外空间来实现吗? 英文: Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: You…

面试题56 - I. 数组中数字出现的次数 一个整型数组 nums 里除两个数字之外,其他数字都出现了两次.请写程序找出这两个只出现一次的数字.要求时间复杂度是O(n),空间复杂度是O(1). 示例 1: 输入:nums = [4,1,4,6] 输出:[1,6] 或 [6,1] 示例 2: 输入:nums = [1,2,10,4,1,4,3,3] 输出:[2,10] 或 [10,2] 限制: 2 <= nums <= 10000 题解思路 我的思路是排序之后逐个判断,符合条件的直接覆盖当前数组…

题目描述: 中文: 给定一个 m x n 的矩阵,如果一个元素为 0,则将其所在行和列的所有元素都设为 0.请使用原地算法. 英文: Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place. class Solution(object): def setZeroes(self, matrix): """ :type matrix: List[Lis…

题目描述 一个整型数组里除了两个数字之外,其他的数字都出现了两次.请写程序找出这两个只出现一次的数字.   思路 将数组的因为就两个数只出现一次,所以,这些数字做异或之后,得到的结果是这两个数做异或的结果,比如  1 2 1 2 3       4 5 5 4 7  做完异或就是3^7   011^111=100 在最后的结果中,从右往左找出现的第一个1,发现在第三位,把100取出来,对原数组每个数进行与运算,与左边与得到的结果都是0   与右边做与运算得到的结果都是1,这样就可以找到这两个子数…

原题地址https://leetcode.com/problems/single-number/ 题目描述Given an array of integers, every element appears twice except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现两次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime complexity.…

原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…

问题: Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?   Single Number I 升级版,一个数组中其它数出现了…

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…

LeetCode 260. Single Number III(只出现一次的数字 III)…

LeetCode 137. Single Number II(只出现一次的数字 II)…

在字符串 s 中找出第一个只出现一次的字符.如果没有,返回一个单空格. s 只包含小写字母. 示例: s = "abaccdeff"返回 "b" s = "" 返回 " " 限制: 0 <= s 的长度 <= 50000 来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/di-yi-ge-zhi-chu-xian-yi-ci-de-zi-fu-lcof //时间复…

［抄题］: Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Ou…

题目描述: 中文: 给定一个由整数组成的非空数组所表示的非负整数,在该数的基础上加一. 最高位数字存放在数组的首位, 数组中每个元素只存储单个数字. 你可以假设除了整数 0 之外,这个整数不会以零开头. 英文: Given a non-empty array of digits representing a non-negative integer, plus one to the integer. The digits are stored such that the most signifi…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 这道题是之前那道 Single Number 单独的数字的延伸,那道题的解法…

Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 本来是一道非常简单的题,但是由于加上了时间复杂度必须是O(n),并且空间复杂度为O(1)…

[1]LeetCode 136 Single Number 题意:奇数个数,其中除了一个数只出现一次外,其他数都是成对出现,比如1,2,2,3,3...,求出该单个数. 解法:容易想到异或的性质,两个相同的数异或为0,那么把这串数从头到尾异或起来,最后的数就是要求的那个数. 代码如下: class Solution { public: int singleNumber(vector<int>& nums) { ; ;i<nums.size();i++) sum ^= nums[i…

Single Number I : Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Solution: 解法不少,贴一种: class…

题目: Given an array of integers, every element appears three times except for one. Find that single one. Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…

题目描述: Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Single Number II Given…

题目地址:here 题目大意:一个整数数组中,只有一个数出现一次,其余数都出现3次,在O(n)时间,O(1)空间内找到这个出现一次的数 对于”只有一个数出现一次,其余数出现2次“的情况,很简单,只要把数组中所有数异或的结果就是这个出现一次的数,leetcode上也有这个题目. 关于本题:我们用一个大小为32的数组cnt来记录:(int数据的每个二进制位1的出现次数)%3,程序中cnt[i]记录第i+1个二进制位.如果某个数出现了三次并且他的第i个二进制位为1,因为做了模3操作,那么该数对数组cn…

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 没辙,智商碾压题.楼主没遇到之前就只会这种做法. public int si…

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路: 这个题是Single Number的进阶版,如果其他的数都出现两次而…

I title: Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路:异或 class Solution { public: int…

Problem 1:一个数组中有一个数字a只出现一次,其他数字都出现了两次.请找出这个只出现一次的数字? 考察知识点:异或运算 思路:比如数字 b^b = 0     a^0 = a 因此,可以将数组中的所有数字进行异或,而最终异或的结果即为所求只出现一次的数字a. 代码: def SingleNumber1(Array): ret = 0 for i in Array: ret ^= i return ret ==========================================…

LintCode 83. Single Number II (Medium) LeetCode 137. Single Number II (Medium) 以下算法的复杂度都是: 时间复杂度: O(n) 空间复杂度: O(1) 解法1. 32个计数器 最简单的思路是用32个计数器, 满3复位0. class Solution { public: int singleNumberII(vector<int> &A) { int cnt[32] = {0}; int res = 0; f…

class Solution { public: int singleNumber(int A[], int n) { ; ; ; i<=bits; i++) { ; ; ; j<n; j++) w += (A[j]>>(i-))&t; result+= (w%)<<(i-); //若是除过一个数之外,其他数重复k次,则将此处的3改为k } return result; } }; 利用二进制的位运算来解决这个问题,比如输入的数组是[2,2,3,2] 它们对应的二…

Single Number Total Accepted: 103745 Total Submissions: 218647 Difficulty: Medium Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you imp…