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CF1005C Summarize to the Power of Two 暴力 map

Summarize to the Power of Two time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output A sequence a1,a2,…,ana1,a2,…,an is called good if, for each element aiai, there exists an element ajaj (i≠ji≠j…

Summarize to the Power of Two（map+思维）

A sequence a1,a2,…,ana1,a2,…,an is called good if, for each element aiai, there exists an element ajaj (i≠ji≠j) such that ai+ajai+aj is a power of two (that is, 2d2d for some non-negative integer dd). For example, the following sequences are good: [5…

CF 1005C Summarize to the Power of Two 【hash/STL-map】

A sequence a1,a2,-,an is called good if, for each element ai, there exists an element aj (i≠j) such that ai+aj is a power of two (that is, 2d for some non-negative integer d). For example, the following sequences are good: [5,3,11] (for example, for…

[USACO12NOV]同时平衡线Concurrently Balanced Strings DP map 思维

题面 [USACO12NOV]同时平衡线Concurrently Balanced Strings 题解 考虑DP. \(f[i]\)表示以\(i\)为左端点的合法区间个数.令\(pos[i]\)表示以\(i\)为左端点,最靠左的合法右端点. 那么有如下转移: \(f[i] = f[pos[i] + 1] + 1\). 1表示[i, pos[i]]这段合法区间,\(f[pos[i] + 1]\)表示在这段合法区间的基础上,还可以在后面拼接更多合法区间. 那么我们的目的就是求\(pos[i]\).…

Bracket Sequences Concatenation Problem括号序列拼接问题（栈+map+思维）

A bracket(括号) sequence is a string containing only characters "(" and ")".A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+&q…

Codeforces 755B：PolandBall and Game（map+思维）

http://codeforces.com/problemset/problem/755/B 题意:A可以喊出n个字符串,B可以喊出m个字符串,如果一个字符串之前被喊过,那么它再也不能喊了,A先喊,最后没得喊的输.问谁赢. 思路:用map判断A.B中字符串一样的个数,因为A可以先喊,然后B再喊,每个人可以喊的数量要减去cnt / 2(如果是奇数,A可以喊多一个),表示被对方喊了.如果最后n<=m则A输,否则A赢,等于的情况是因为A先喊,B再喊,到最后A会输. #include <cstdio&…

mind map 思维导图

<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>Mind Map</title> <meta name="description" content="A mind map editor, showing how subtrees can be moved, copied, deleted, and laid…

HDU 6623 Minimal Power of Prime（思维）题解

题意: 已知任意大于\(1\)的整数\(a = p_1^{q_1}p_2^{q_2} \cdots p_k^{q_k}\),现给出\(a \in [2,1e18]\),求\(min\{q_i\},q \in [1, k]\).即求质因数分解后,最小指数是多少. 思路: 因为\(a \in [2,1e18]\),所以我们现打一个\(1e4\)以内的质数表,然后直接求出\(1e4\)以内的情况. 上面弄完了,那么现在最多只有\(4\)个质因子,情况如下: \(n = p^4\),这种情况就是\(4\…

IDE引入mindmap插件，在项目中添加思维导图

1.打开IDE,file--settings--plugins,搜索IDEA Mind Map 2.点击install,进行下载,然后按照提示restart重启IDEA,安装完成 3.创建mind map思维导图--在项目任意目录下,点击右键,new--选择Empty Mind Map,即可创建自己的项目思维导图 示例:…

Codeforces Round #496 (Div. 3) ABCDE1

//B. Delete from the Left #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <set> #include <map> #include <vector> using namespace std; const int inf=0x3f3f3f3f; ; char a[N],b[…