通讯系统 We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choos…

Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choose from several manufacturers. Same devices from two manufacturers d…

题意: 给出n个工厂的产品参数带宽b和价格p,在这n个工厂里分别选1件产品共n件,使B/P最小,其中B表示n件产品中最小的b值,P表示n件产品p值的和. 输入 iCase n 表示iCase个样例n个工厂 m1 p1 b1 p2 b2..pm1 bm1 //第一个工厂有m1个同种类不同参数的产品,每一个产品的参数分别是p1 b1 p2 b2 m2 p1 b1 p2 b2..pm2 bm2 ... mn p1 b1 p2 b2..pmn bmn 思路: 排序,先把b从小到大排序,然后把p从小到大排…

看题传送门:http://poj.org/problem?id=1018 题目大意: 某公司要建立一套通信系统,该通信系统需要n种设备,而每种设备分别可以有m个厂家提供生产,而每个厂家生产的同种设备都会存在两个方面的差别:带宽bandwidths 和 价格prices. 现在每种设备都各需要1个,考虑到性价比问题,要求所挑选出来的n件设备,要使得B/P最大. 其中B为这n件设备的带宽的最小值,P为这n件设备的总价. 思路: 贪心+枚举 要使得B/P最大,则B应该尽量大,而P尽量小. 可以按照价格…

题意:给你一个图,图中点之间会有边权,现在问题是把图分成两部分,使得两部分之间边权之和最大. 目前我所知道的有四种做法: 方法一:状态压缩 #include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> /* 用状态压缩枚举,297ms. 题意:给你一个图,图中点之间会有边权,现在问题是把图分成两部分,使得两部分之间边权之和最大. 情况是对称的,也就是说枚举所有的…

Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21631   Accepted: 7689 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices.…

题意:求n个串的字典序最小的最长公共子串. 解法:枚举第一个串的子串,与剩下的n-1个串KMP匹配,判断是否有这样的公共子串.从大长度开始枚举,找到了就break挺快的.而且KMP的作用就是匹配子串,近乎O(n)的速度,很快. P.S.对于字符串要仔细!!! #include<cstdio> #include<cstdlib> #include<cstring> #include<iostream> using namespace std; ; int n;…

题目链接 题意 :给你r*c的一块稻田,每个点都种有水稻,青蛙们晚上会从水稻地里穿过并踩倒,确保青蛙的每次跳跃的长度相同,且路线是直线,给出n个青蛙的脚印点问存在大于等于3的最大青蛙走的连续的脚印个数. 思路 : 暴力了一下,顺便剪剪枝就可以过.... //POJ1054 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> using namespac…

Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 22380   Accepted: 7953 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices.…

题目链接:http://poj.org/problem?id=1018 题目大意:有n种通讯设备,每种有mi个制造商,bi.pi分别是带宽和价格.在每种设备中选一个制造商让最小带宽B与总价格P的比值B/P最大. 解法是枚举最小带宽B,每种设备在带宽大于B的制造商中找价格最小的,最后取比值最大的. 详见代码: #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> using…