Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1:             Inp…

  Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: divide…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 这道题让我们求两数相除,而且规定我们不能用乘法,除法和取余操作,那么我们还可以用另一神器位操作Bit Operation,思路是,如果被除数大于或等于除数,则进行如下循环,定义变量t等于除数,定义计数p,当t的两倍小于等于被除数时,进行如下循环,t扩大一倍,p扩大一倍,然后更…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

Divide two integers without using multiplication, division and mod operator. 分析:题目意思很容易理解,就是不用乘除法和模运算求来做除法,很容易想到的一个方法是一直做减法,然后计数,超时.在网上找到一种解法,利用位运算,意思是任何一个整数可以表示成以2的幂为底的一组基的线性组合,即num=a_0*2^0+a_1*2^1+a_2*2^2+...+a_n*2^n.基于以上这个公式以及左移一位相当于乘以2,我们先让除数左移直到…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

Divide two integers without using multiplication, division and mod operator. If it is overflow, return 2147483647 Have you met this question in a real interview?     Example Given dividend = 100 and divisor = 9, return 11. LeetCode上的原题,请参见我之前的博客Divid…

不使用乘号,除号和取模符号将两数相除.如果溢出返回 MAX_INT.详见:https://leetcode.com/problems/divide-two-integers/description/ Java实现: 位操作Bit Operation,思路是:如果被除数大于或等于除数,则进行如下循环,定义变量t等于除数,定义计数p,当t的两倍小于等于被除数时,进行如下循环,t扩大一倍,p扩大一倍,然后更新res和m. class Solution { public int divide(int d…

题目 两个整数相除 将两个整数相除,要求不使用乘法.除法和 mod 运算符. 如果溢出,返回 2147483647 . 样例 给定被除数 = 100 ,除数 = 9,返回 11 解题  15%的通过率,减法,位运算?表示不知道如何下手. 法一:利用减法,超时,人工直接去除的一些情况太流氓. public class Solution { /** * @param dividend the dividend * @param divisor the divisor * @return the re…