Description Yi Sima was one of the best counselors of Cao Cao. He likes to play a funny game himself. It looks like the modern Sudoku, but smaller. Actually, Yi Sima was playing it different. First of all, he tried to generate a 4×4 board with every…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=5547 题目: Sudoku Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 2372    Accepted Submission(s): 804 Problem Description   Yi Sima was one of the be…

题目链接:HDU-5547 http://acm.hdu.edu.cn/showproblem.php?pid=5547 正所谓:骗分过样例,暴力出奇迹. 解题思想(暴力出奇迹(DFS+回溯)): 1. 依次在空格里面填上“1~9”,并检查这个数字是否合法(其所在的行.列,以及3X3的子区域里不存在重复的数字).如果合法,则前进到下一个格子. 2. 如果在某个格子里,从“1”到“9”都不合法,这说明前面某个格子填错了.这时就回退到上一格,继续试.例如,如果上一格已填的数字是3,就继续试4,5,6…

Sudoku Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 596    Accepted Submission(s): 216 Problem Description Yi Sima was one of the best counselors of Cao Cao. He likes to play a funny game him…

Sudoku Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1064    Accepted Submission(s): 362 Problem Description Yi Sima was one of the best counselors of Cao Cao. He likes to play a funny game hi…

题目链接:https://cn.vjudge.net/problem/HDU-5547 具体思路:对于每一位上,我们可以从1到4挨着去试, 具体判断这一位可不可以的时候,看当前这一位上的行和列有没有冲突,以及他所在的2*2的方格中有没有矛盾的. AC代码: #include <iostream> #include <string> #include <deque> #include <stack> #include<cmath> #include…

题意:数独. 析:由于只是4*4,完全可以暴力,要注意一下一些条件,比如2*2的小方格也得是1234 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include &…

Problem Description Yi Sima was one of the best counselors of Cao Cao. He likes to play a funny game himself. It looks like the modern Sudoku, but smaller. Actually, Yi Sima was playing it different. First of all, he tried to generate a × board with…

Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…

http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…