Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks tha…

Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14125    Accepted Submission(s): 8269 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) whe…

前言 最近板子题刷多了-- 题意 一个 \(8\times 8\) 的棋盘,问马从起点到终点的最短步数为多少. \(\sf Solution\) 要求最短路径嘛,显然 bfs 更优. 读入 这个读入处理有点麻烦-- 我们可以把表示行的字符转化为数字,即 ch-'a'+1 . 搜索 将起点入队,每次获取队首元素并相应扩展,记录步数. 搜到的第一条路径就是最短路径,直接输出 step . \(\sf Code\) #include<cstdio> #include<cstring> #…

HDU1372:Knight Moves(BFS)   Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu   Description   A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves…

题目链接 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He think…

题目链接:http://poj.org/problem?id=2243 Knight Moves Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14500   Accepted: 8108 Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortes…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] bfs模板题 [代码] /* 1.Shoud it use long long ? 2.Have you ever test several sample(at least therr) yourself? 3.Can you promise that the solution is right? At least,the main ideal 4.use the puts("") or putchar() or pr…

1450:[例 3]Knight Moves  题解 这道题可以用双向宽度搜索优化(总介绍在  BFS ) 给定了起始状态和结束状态,求最少步数,显然是用BFS,为了节省时间,选择双向BFS. 双向BFS,即从起点向终点搜,从终点向起点搜,扩展各自的状态,直到出现两者扩展的状态重合 优化:每次选择结点少的扩展 看一下骑士可以到达那些点呢?? 所以当然要开两个队列啦 设定: 1. dis[ i ][ a ][ b ]:队列 i ,从起点(a,b)至少多少步 2.    v[ i ][ a ][ b…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7661    Accepted Submission(s): 4567 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to…

最近在学习广搜  这道题同样是一道简单广搜题=0= 题意:(百度复制粘贴0.0) 题意:给出骑士的骑士位置和目标位置,计算骑士要走多少步 思路:首先要做这道题必须要理解国际象棋中骑士的走法,国际象棋中,骑士是在一个3*2的格子中进行对角线移动,通过画图很容易就知道骑士最多可以朝八个方向移动,那么就朝8个方向进行BFS即可 //细节注意: 1.输入开始结束坐标时需要保存  所以我用了全局变量  因为输出还需要他们=0=: 2.依旧是用bool类型进行map保存,防止内存超限, 0表示还未走过, 1…

Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10542    Accepted Submission(s): 6211 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) wh…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10372    Accepted Submission(s): 6105 Problem Description A friend of you is doin…

简单搜索,我这里用的是dfs,由于棋盘只有8x8这么大,于是想到dfs应该可以过,后来由于边界的问题,TLE了,改了边界才AC. 这道题的收获就是知道了有些时候dfs没有特定的边界的时候要自己设置一个合适的边界.这题推导可知,任意两点之间马踩6步之内一定能够到达,6步之内还未搜到说明绝对不是最优结果,果断退出.所以这里的res开始时最小设定为6即可,随着设的res的增大,运行时间越来越多,因为深搜可以有很多的分支,不采取较小的边界的话,可能会浪费很多时间在无用的搜索上,所以需要如此剪枝. 反复提…

题 Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks that the…

这道题实到bfs的题目,很简单,不过搜索的方向变成8个而已,对于不会下象棋的会有点晕. #include <iostream> #include <stdio.h> #include <string.h> #include <queue> using namespace std; ][]; ][] = {{-,-},{-,},{-,},{,},{,},{,-},{,-},{-,-}}; typedef struct { int x,y,count; }nod…

其实手写模拟一个队列也挺简单的,尤其是熟练以后. 尼玛,这题欺负我不懂国际象棋,后来百度了下,国际象棋里骑士的走法就是中国象棋里面的马 所以搜索就有八个方向 对了注意初始化标记数组的时候,不要把起点标记为已走过. 因为测试数据里面有一组 f6 f6,此时样例输出的是0 //#define LOCAL #include <iostream> #include <cstdio> #include <cstring> using namespace std; struct P…

题意:给出8*8的棋盘,给出起点和终点,问最少走几步到达终点. 因为骑士的走法和马的走法是一样的,走日字形(四个象限的横竖的日字形) 另外字母转换成坐标的时候仔细一点(因为这个WA了两次---@_@) #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue> #define maxn 105 using namespace s…

  // 题意:输入标准国际象棋棋盘上的两个格子,求马最少需要多少步从起点跳到终点 BFS求最短路: bfs并维护距离状态cnt, vis记录是否访问过 #include<cstdio> #include<cstring> #include<iostream> #include<string> #include<algorithm> #include<queue> using namespace std; int r1, c1, r2…

题意:8*8国际象棋棋盘,求马从起点到终点的最少步数. 编写时犯的错误:1.结构体内没构造.2.bfs函数里返回条件误写成起点.3.主函数里取行标时未注意书中的图. #include<iostream> #include<cstdio> #include<cstring> #include<string> #include<sstream> #include<cctype> #include<cmath> #include…

Knight Moves Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13222   Accepted: 7418 Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that v…

1.链接地址: http://bailian.openjudge.cn/practice/1915 http://poj.org/problem?id=1915 2.题目: 总Time Limit: 1000ms Memory Limit: 65536kB Description BackgroundMr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from o…

题目例如以下: Knight Moves  A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks t…

Knight Moves Time Limit: 2 Seconds      Memory Limit: 65536 KB A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares…

Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks tha…

Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks tha…

题目地址:1936. Knight Moves 思路: 这道题一开始不理解题意…orz...囧,看大神们理解的. 题意是说一个8*8的国际象棋,骑士以马的形式走动(“日”字型),指定两个点,输出最小的步骤. 可以利用广度搜索解决. 具体代码如下: #include <iostream> #include <queue> #include <cstring> #include <string> using namespace std; , -, -, -, ,…

http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6439    Accepted Submission(s): 3886 Problem Description A friend of you is doing res…

Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8831    Accepted Submission(s): 5202 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) wher…

解题思路:BFS 1)马的跳跃方向 在国际象棋的棋盘上,一匹马共有8个可能的跳跃方向,如图1所示,按顺时针分别记为1~8,设置一组坐标增量来描述这8个方向: 2)基本过程 设当前点(i,j),方向k,沿方向k跳一步后的新点(newi,newj):每走一步,都要判断新点(newi,newj)是否还在棋盘上: 若1£newi£8且1£newj£8,则新点仍在棋盘上,则还需判断该点是否已经走过,即 若visited[newi][newj]=0,表示该步可走: 若visited[newi][newj]=…

题目链接:http://poj.org/problem?id=2243 启发式搜索:启发式搜索就是在状态空间中的搜索对每一个搜索的位置进行评估,得到最好的位置,再从这个位置进行搜索直到目标.这样可以省略大量无畏的搜索路径,提到了效率.在启发式搜索中,对位置的估价是十分重要的.采用了不同的估价可以有不同的效果. 估价函数:从当前节点移动到目标节点的预估费用:这个估计就是启发式的.在寻路问题和迷宫问题中,我们通常用曼哈顿(manhattan)估价函数(下文有介绍)预估费用. A*算法与BFS:可以这…