Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ. 3…

[LeetCode]99. Recover Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/recover-binary-search-tree/description/ 题目描述: Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without chan…

题目链接:Recover Binary Search Tree | LeetCode OJ Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constan…

Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 基本…

Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. 互换二叉搜索树中两个位置错误的节点. 思路: 预设三个指针pre,p1,p2.p1用来指向第一个出错的节点,p2用来指向第二个出错的节点. 出错情况有两种,即p1和p2相邻,p1和p2不相邻. 中序遍历此二叉树,用…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. 来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/recover-binary-search-tree著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. [题意分析] 对于一个BST应该了解的一个重…

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Problem Link: https://oj.leetcode.com/problems/recover-binary-search-tree/ We know that the inorder traversal of a binary search tree should be a sorted array. Therefore, we can compare each node with its previous node in the inorder to find the two…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. 题意: 一颗二叉搜索树中有2个结点的元素被误换了,要求恢复二叉搜索树的原状. 思路: 中序遍历BST,若发现一次逆序,说明是两个相连结点的误换,直接交换结点的值:若发现两次逆序,则为不相连的两个结点误换,交换错误的结点即可.用一个变量保存先前结点的状态,若发生逆序则记…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}"…