For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is [1, 2, 3, 3, 4, 5, 10], for given ta…

14. First Position of Target [easy] For a given sorted array (ascending order) and a targetnumber, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is […

找指定target的最左位置. class Solution { /** * @param nums: The integer array. * @param target: Target to find. * @return: The first position of target. Position starts from 0. */ public int binarySearch(int[] nums, int target) { if(nums == null) return -1;…

Binary search is a famous question in algorithm. For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If…

For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is [1, 2, 3, 3, 4, 5, 10], for given ta…

For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. 来源: http://www.lintcode.com/en/problem/first-position-of-tar…

找出指定target的位置(没有此数时为按顺序应当位置). public class Solution { /** * param A : an integer sorted array * param target : an integer to be inserted * return : an integer */ public int searchInsert(int[] A, int target) { if(A == null) return -1; if(A.length == 0…

Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (2016-02-10) For more problems and solutions, you can see my LintCode repository. I'll keep updating for full summary and better solutions. See cnblogs t…

254. Drop Eggs https://www.lintcode.com/problem/drop-eggs/description?_from=ladder&&fromId=1 28. Search a 2D Matrix https://www.lintcode.com/problem/search-a-2d-matrix/description?_from=ladder&&fromId=1 思路1: 1. find the row index, the last…

--------------------------------------------------------------- 本文使用方法:所有题目,只需要把标题输入lintcode就能找到.主要是简单的剖析思路以及不能bug-free的具体细节原因. ---------------------------------------------------------------- ------------------------------------------- 第九周:图和搜索. ---…