#-*- coding: UTF-8 -*-#双指针思想,两个指针相隔n-1,每次两个指针向后一步,当后面一个指针没有后继了,前面一个指针的后继就是要删除的节点# Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def re…

Remove Nth Node From End of List Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:链表, 删除节点,双指针,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 双指针 日期 题目地址:https://leetcode.com/problems/remove-nth-node-from-end-of-list/description/ 题目描述 Given a linked list,…

一天一道LeetCode系列 (一)题目 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->…

题目说明 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: G…

题目: 思路:如果链表为空或者n小于1,直接返回即可,否则,让链表从头走到尾,每移动一步,让n减1. 1.链表1->2->3,n=4,不存在倒数第四个节点,返回整个链表 扫过的节点依次:1-2-3 n值得变化:3-2-1 2.链表1->2->3,n=3 扫过的节点依次:1-2-3 n值得变化:2-1-0 3.链表1->2->3,n=2 扫过的节点依次:1-2-3 n值得变化:1-0--1 当走到链表结尾时:1.n>0,说明链表根本没有第n个节点,直接返回原链表:…

#-*- coding: UTF-8 -*- # Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def removeElements(self, head, val):        """      …

#-*- coding: UTF-8 -*- # Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def deleteDuplicates(self, head):        if head==None or head.…

#-*- coding: UTF-8 -*- class Solution(object):    def removeElement(self, nums, val):        """        :type nums: List[int]        :type val: int        :rtype: int        """        for i in range(len(nums)-1,-1,-1):      …

#-*- coding: UTF-8 -*-class Solution(object):    def removeDuplicates(self, nums):        """        :type nums: List[int]        :rtype: int        """        if len(nums)<=1:return len(nums)        pre=0;next=1        wh…