题目 最小子串覆盖 给定一个字符串source和一个目标字符串target,在字符串source中找到包括所有目标字符串字母的子串. 样例 给出source = "ADOBECODEBANC",target = "ABC" 满足要求的解  "BANC" 注意 如果在source中没有这样的子串,返回"",如果有多个这样的子串,返回起始位置最小的子串. 挑战 要求时间复杂度为O(n) 说明 在答案的子串中的字母在目标字符串中是否…

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example,S = "ADOBECODEBANC"T = "ABC" Minimum window is "BANC". Note:If there is no such window i…

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). Example: Input: S = "ADOBECODEBANC", T = "ABC" Output: "BANC" Note: If there is no such window in S…

问题描述:给定字符串S,子串T,求S中包含T的最小窗口 Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example,S = "ADOBECODEBANC"T = "ABC" Minimum window is "BANC". 算法分析:…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 滑动窗口 日期 题目地址: https://leetcode.com/problems/minimum-window-substring/description/ 题目描述 Given a string S and a string T, find the minimum window in S which will contain all the…

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). Example: Input: S = "ADOBECODEBANC", T = "ABC" Output: "BANC" Note: If there is no such window in S…

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example,S ="ADOBECODEBANC"T ="ABC" Minimum window is"BANC". Note: If there is no such window in…

题目 带最小值操作的栈 实现一个带有取最小值min方法的栈,min方法将返回当前栈中的最小值. 你实现的栈将支持push,pop 和 min 操作,所有操作要求都在O(1)时间内完成. 解题 可以定义一个数组或者其他的存储最小值,第i个元素,表示栈中前i个元素的最小值. 定义两个ArrayList来存储栈,一个ArrayList存储当前栈中的元素,一个ArrayList存储最小栈,并且其第i个元素表示栈中前i个元素的最小值,这样两个栈的长度是始终一样的 入栈:最小栈需要加入的元素是 当前要入的元…

Given strings S and T, find the minimum (contiguous) substring W of S, so that T is a subsequenceof W. If there is no such window in S that covers all characters in T, return the empty string "". If there are multiple such minimum-length windows…

一.题目说明 题目76. Minimum Window Substring,求字符串S中最小连续字符串,包括字符串T中的所有字符,复杂度要求是O(n).难度是Hard! 二.我的解答 先说我的思路: (1)统计t中每个字符出现的次数, (2)用hash存储s中出现t中字符的位置, (3)计算最短字符串. 思路有了,惭愧的是,这个题目,我没做出来. 后来参考大神的实现了,用"滑动窗口"实现. 代码如下: class Solution{ public: string minWindow(s…