A character string is said to have period k if it can be formed by concatenating one or more repetitionsof another string of length k. For example, the string ”abcabcabcabc” has period 3, since it is formedby 4 repetitions of the string ”abc”. It als…

发信人: fennec (fennec), 信区: Algorithm 标 题: acm 总结 by fennec 发信站: 吉林大学牡丹园站 (Wed Dec 8 16:27:55 2004) ACM总结(fennec) 其实在北京比赛完的时候,我就想写了,不过还是早了点,直到上海比赛结束,大家的心中都不是太好受.郭老师有句话:你们这样做也是对的,不成功就成仁.让我的心也能安慰了不少. 我是从大一下学期开始接触ACM的,那时候我们学校才刚刚起步,siyee,wjiang师兄可以说是我的领路人了…

Given a string ss of length nn and integer kk (1≤k≤n1≤k≤n). The string ss has a level xx, if xx is largest non-negative integer, such that it's possible to find in ss: xx non-intersecting (non-overlapping) substrings of length kk, all characters of t…

Given two strings,  a and , b find and print the total number of ways to insert a character at any position in string a such that the length of the Longest Common Subsequence of characters in the two strings increases by one. Input Format The first l…

1 数组排序 1.1 问题 本案例实现一个整型数组排序的函数,数组排序的规则由传递的规则函数决定. 1.2 方案 首先定义一个整型数组排序函数sortInts,该函数有一个整型数组类型的参数,该参数必须是输入输出参数inout,否则并不能修改数组的值.另外还有一个(Int,Int)->Bool函数类型的参数rule,该参数用于提供数组的排序规则. 然后实现函数sortInts,这里采用数组的冒泡排序算法来实现排序. 接下来实现一个数组排序的规则函数rule1,该函数是(Int,Int)->Bo…

[POJ3096]Surprising Strings 试题描述 The D-pairs of a string of letters are the ordered pairs of letters that are distance D from each other. A string is D-unique if all of its D-pairs are different. A string is surprising if it is D-unique for every pos…

Counterfeit Dollar Time Limit: 1 Sec  Memory Limit: 64 MB Submit: 415  Solved: 237 Description Sally Jones has a dozen Voyageur silver dollars. However, only eleven of the coins are true silver dollars; one coin is counterfeit even though its color a…

E - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…

题意:输入很多字符串,以星号结束.判断每个字符串是不是“Surprising Strings”,判断方法是:以“ZGBG”为例,“0-pairs”是ZG,GB,BG,这三个子串不相同,所以是“0-unique”,“1-pairs”是ZB,GG,这两个也是不同的,所以是“1-unique”,“2-pairs”是ZG,所以是“2-unique”:综合起来是“Surprising Strings”. 思路:用map就可以,做的时候手欠用了暴搜,结果发现竟然0ms过了,不科学.而用map花了16ms非常…

提高你的Java代码质量吧:推荐使用枚举定义常量 一.分析 常量的声明是每一个项目中不可或缺的,在Java1.5之前,我们只有两种方式的声明:类常量和接口常量.不过,在1.5版之后有了改进,即新增了一种常量声明方式,枚举常量.代码如下: enum Season{ Spring,Summer,Autumn,Winter; } 二.场景 那么枚举常量与我们的经常使用的类常量和静态常量比有什么优势呢? 1.枚举常量更简单  先把Season枚举翻译成接口,代码如下: interface Season{…

术语表 Iterator:枚举器(迭代器) 如果你正在创建一个表现和行为都类似于集合的类,允许类的用户使用foreach语句对集合中的成员进行枚举将会是很方便的.这在C# 2.0中比 C# 1.1更容易实现一些.作为演示,我们先在 C# 1.1中为一个简单的集合添加枚举,然后我们修改这个范例,使用新的C#2.0 枚举构建方法. 我们将以创建一个简单化的List Box作为开始,它将包含一个8字符串的数组和一个整型,这个整型用于记录数组中已经添加了多少字符串.构造函数将对数组进行初始化并使用传递进…

花了半个月,才搞定驱动中的枚举部分,现在说linux的枚举,windows可能有差别. 代码我会贴在后面,现在只是实现枚举,你可能对代码不感兴趣,我就不分析代码了,你可以看看 在<自娱自乐1>中的模板,比较一下,我做了什么,这会给你写udc驱动提供个思路.我直接分析 调试打印,就是枚举过程,我们从代码看枚举.打印位置可以在下面的代码里找到. 如果你要弄懂驱动代码中涉及枚举的地方,你就仔细看看代码在那打印的,这个对你完成一个udc驱 动有帮助. 如果你只是想简单了解枚举你就看看我分析的调试打印就…

正反两遍扩展KMP,维护公共长度为L时.出如今最左边和最右边的位置. . .. 然后枚举推断... E. Martian Strings time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output During the study of the Martians Petya clearly understood that the Mart…

A. Mike and palindrome time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output Mike has a string s consisting of only lowercase English letters. He wants to change exactly one character from the s…

You are given n strings s1, s2, ..., sn consisting of characters 0 and 1. m operations are performed, on each of them you concatenate two existing strings into a new one. On the i-th operation the concatenation saisbi is saved into a new string sn + …

Description You are given n strings s1, s2, ..., sn consisting of characters 0 and 1. m operations are performed, on each of them you concatenate two existing strings into a new one. On the i-th operation the concatenation saisbi is saved into a new…

Problem Statement You are given a string S consisting of digits between 1 and 9, inclusive. You can insert the letter + into some of the positions (possibly none) between two letters in this string. Here, + must not occur consecutively after insertio…

这题调得我心疲力竭...Educational Round 5就过一段时间再发了_(:з」∠)_ 先后找了三份AC代码对拍,结果有两份都会在某些数据上出点问题...这场的数据有点水啊_(:з」∠)_[然而卡掉本弱还是轻轻松松的] 题目链接:616F - Expensive Strings 题目大意:给出\(n\)个字符串\(t_i\)以及\(n\)个数\(c_i\),定义\(p_{s,i}\)为字符串\(s\)在\(t_i\)中出现的次数,\(f(s)=\sum_{i=1}^{n}c_i\cdo…

题目链接:传送门 题目: E. Check Transcription time limit per test seconds memory limit per test megabytes input standard input output standard output One of Arkady's friends works at a huge radio telescope. A few decades ago the telescope has sent a signal s t…

[CC-BSTRLCP]Count Binary Strings 题目大意: 对于一个长度为\(n\)的\(\texttt0/\texttt1\)串\(S\),如果存在一个切分\(i\),使得\(S_{[1,i]}\)与\(S_{[i+1,n]}\)的LCP长度\(>k\),那么称\(i\)是\(S\)的精准切分. 如果\(S\)至少有\(m\)个精准切分,那么称\(S\)是一个切分串. 给定\(n,k,m\),求有多少长度为\(n\)的切分串. \(1\le T\le 5\) \(1\le n…

--------------------------------------------------------------------- 枚举: // main.c #include <stdio.h> ; ; ; int main(int argc, const char * argv[]) { /* 常量符号化:用符号而不是具体的数字来表示程序中的数字; 这样看到符号才能知道背后的意思 */ ; char *colorName = NULL; printf("输入颜色代码:&q…

枚举部分 Enumeration part 使用枚举我们可以定义一些有名字的数字常量. 枚举通过 enum关键字来定义. Using enumerations, we can define some numeric constants with names. Enumeration is defined by the enum keyword. enum Direction { Up = 1, Down, Left, Right } 枚举是在运行时真正存在的一个对象,其中一个原因是因为这样可以从…

时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 Lara Croft, the fiercely independent daughter of a missing adventurer, must push herself beyond her limits when she discovers the island where her father disappeared. In this mysterious island, Lara finds a tomb…

E. Dreamoon and Strings 题目连接: http://www.codeforces.com/contest/476/problem/E Description Dreamoon has a string s and a pattern string p. He first removes exactly x characters from s obtaining string s' as a result. Then he calculates that is defined…

https://blog.csdn.net/u012372584/article/details/53735242 版权声明:本文为博主原创文章,未经博主允许不得转载. https://blog.csdn.net/u012372584/article/details/53735242 借鉴内容来自VC++驿站:VC驿站 ①.使用 GetWindow 进行窗口枚举: This function retrieves the handle to a window that has the specif…

题目链接:https://hihocoder.com/problemset/problem/1829 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 Lara Croft, the fiercely independent daughter of a missing adventurer, must push herself beyond her limits when she discovers the island where her father disappe…

UVA10298 Power Strings hash+乘法逆元+一点点数学知识 我们用取余法算出主串的hash,然后从小到大枚举子串的长度 显然,如果若干个子串的复制的hash值之和等于主串的hash值,那么答案就得到了. 然后我们计算子串(设子串长度为 i )的hash值: hash=t*(+base^i+base^2i+...+base^(len-i)) 如果直接暴力求,那么显然会TLE 于是我们进行推导: 设: Si=+base^i+base^2i+...+base^(len-i) S=…

题面 [USACO12NOV]同时平衡线Concurrently Balanced Strings 题解 考虑DP. \(f[i]\)表示以\(i\)为左端点的合法区间个数.令\(pos[i]\)表示以\(i\)为左端点,最靠左的合法右端点. 那么有如下转移: \(f[i] = f[pos[i] + 1] + 1\). 1表示[i, pos[i]]这段合法区间,\(f[pos[i] + 1]\)表示在这段合法区间的基础上,还可以在后面拼接更多合法区间. 那么我们的目的就是求\(pos[i]\).…

C. Two strings time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given two strings a and b. You have to remove the minimum possible number of consecutive (standing one after another)…

Gene and Gina have a particular kind of farm. Instead of growing animals and vegetables, as it is usually the case in regular farms, they grow strings. A string is a sequence of characters. Strings have the particularity that, as they grow, they add…