判断一棵树中是否包含另一棵子树(包含是,两棵树重合处的根节点之下的子节点都相等) 有两种方法: 方法二:递归写法 //方法一:可以借鉴之前序列化的题目,如果序列化得到的序列一样就是相同的树 //方法二:用递归来写十分的简洁,我们先从s的根结点开始,跟t比较,如果两棵树完全相同,那么返回true,否则就分别对s的左子结点和右子结点调用递归再次来判断是否相同,只要有一个返回true了,就表示可以找得到. class Solution { public: bool isSubtree(TreeNode…

题目如下: Given two non-empty binary trees s and t, check whether tree t has exactly the same structure and node values with a subtree of s. A subtree of s is a tree consists of a node in s and all of this node's descendants. The tree s could also be con…

Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归的解题思路: 递归当前结点,分一下四种情况考虑:①结点为空时返回0:②结点没有右子树时,返回左子树最小值+1:③结点没有左子树时,返回右子树最小值+1:④当结点双子齐全时,返回…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 递归解题思路: ①结点为空时,返回0:②当前结点的深度 = max(两个孩子结点各自最大深度)+ 1 /** * Definition for binary tree * stru…

606. Construct String from Binary Tree [easy] You need to construct a string consists of parenthesis and integers from a binary tree with the preorder traversing way. The null node needs to be represented by empty parenthesis pair "()". And you…

344. Reverse String[easy] Write a function that takes a string as input and returns the string reversed. Example:Given s = "hello", return "olleh". 解法一: class Solution { public: string reverseString(string s) { , end = s.length() - ; w…

[BZOJ1803]Spoj1487 Query on a tree III Description You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels. Input…

[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…

[BZOJ2843]极地旅行社(Link-Cut Tree) 题面 BZOJ 题解 \(LCT\)模板题呀 没什么好说的了.. #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath> #include<algorithm> #include<set> #include<map> #includ…

[BZOJ4530]大融合(Link-Cut Tree) 题面 讨厌权限题!!! Loj链接 题目描述 小强要在 N个孤立的星球上建立起一套通信系统.这套通信系统就是连接 N个点的一个树.这个树的边是一条一条添加上去的.在某个时刻,一条边的负载就是它所在的当前能够联通的树上路过它的简单路径的数量. 例如,在上图中,现在一共有五条边.其中,(3,8)这条边的负载是 6,因为有六条简单路径 2−3−8, 2−3−8−7, 3−8, 3−8−7, 4−3−8, 4−3−8−72-3-8, 2-3-8-…