题意是强盗能隔个马抢马,看如何获得的价值最高 动态规划题需要考虑状态,阶段,还有状态转移,这个可以参考<动态规划经典教程>,网上有的下的,里面有大量的经典题目讲解 dp[i]表示到第i匹马时的最大价值是多少, 因此所有的dp[i] = max(dp[i-2]+nums[i],dp[i-1]) (其中dp[0] = nums[0] dp[1] = max(nums[0],nums[1]): class Solution { public: int rob(vector<int>&am…

198. House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

思路: 代码: class Solution { public: int rob(vector<int> &num) { ; int size=num.size(); ) ]; vector<int> dp; dp.resize(size,); dp[]=num[]; dp[]=(num[]>num[])?num[]:num[]; ]>dp[])?dp[]:dp[]; ;i<size;++i){ dp[i]=max(num[i]+dp[i-],dp[i-]…

**322. Coin Change 思路:动态规划,构造一个数组,存入当前index最少需要多少个coin public int coinChange(int[] coins, int amount) { if(coins == null || coins.length == 0 || amount <= 0) return 0; //表示Index需要多少个coin int[] dp = new int[amount + 1]; for(int i = 1; i < amount + 1;…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

一.题目 House Robber(一道Leetcode上的关于动态规划的简单题目)具体描述如下: There is a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent hous…

House Robber题目链接 House Robber II题目链接 1. House Robber 题目要求: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjac…

2018-04-29 20:20:56 House Robber问题是leetcode上经典的系列题,这里对其中的题目做一个讲解. 198. House Robber 问题描述: 问题求解: 本质上就是求解不连续取数的情况下能获得最大价值.可以使用动态规划来解决. dp[i][0]:第i个数没有取能获得的最高价值 dp[i][1]:第i个数取能获得的最高价值 初始值:dp[-1][0] = 0,dp[-1][1] = -INF 递推关系式:dp[i][0] = max(dp[i - 1][0],…

题目描述: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will…