A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts. Example 1: Input: S = "abab…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Input: head = 1->4->3->2->…

/* 这个题是medium的意思应该是用双指针的方法做,如果使用下边的新建链表的方法,就是easy的题目了 双指针会用到很多链表的相连操作 */ public ListNode partition(ListNode head, int x) { ListNode s = null; ListNode b = null; ListNode temp=null,res=null; while (head!=null) { int cur = head.val; if (head.val<x) { i…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example, Given 1->4->3->…

LeetCode:分割链表[86] 题目描述 给定一个链表和一个特定值 x,对链表进行分隔,使得所有小于 x 的节点都在大于或等于 x 的节点之前. 你应当保留两个分区中每个节点的初始相对位置. 示例: 输入: head = 1->4->3->2->5->2, x = 3 输出: 1->2->2->4->3->5 题目分析 这道题有总体思路是从头到尾扫描一次链表,将那些小于的节点放在一条链表上,大的放到一条链表上,最后两条一拼接即可. 由于题目给…

博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech…

2.4 Write code to partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. LeetCode上的原题,请参见我之前的博客Partition List 划分链表.…

LeetCode: Palindrome Partition Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], [&q…