Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banned, and that the answer is unique. Words in the list of banned words are…
原题链接在这里:https://leetcode.com/problems/most-common-word/description/ 题目: Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banne…
problem 819. Most Common Word solution: class Solution { public: string mostCommonWord(string paragraph, vector<string>& banned) { unordered_map<string, int> m; string word = ""; ; i<paragraph.size(); ) { string word = "&…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 正则+统计 日期 题目地址:https://leetcode.com/problems/most-common-word/description/ 题目描述 Given a paragraph and a list of banned words, return the most frequent word that is not in the li…
[抄题]: Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banned, and that the answer is unique. Words in the list of banned word…
static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string mostCommonWord(string paragraph, vector<string>& banned) { unordered_map<string,int> simap; for(string s:banned) simap[s]=-; ,fl…
819. Most Common Word Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banned, and that the answer is unique. Words in the lis…
对文件进行词频统计,是一个大数据领域的hello word级别的应用,来看下实现有多简单: 1 Linux单机处理 egrep -o "\b[[:alpha:]]+\b" test_word.log|sort|uniq -c|sort -rn|head -10 2 Spark分布式处理(Scala) val sparkConf = new SparkConf() val sc = new SparkContext(sparkConf) sc.textFile("test_wo…
#瓦登尔湖词频统计: import string path = 'D:/python3/Walden.txt' with open(path,'r',encoding= 'utf-8') as text: words = [raw_word.strip(string.punctuation).lower() for raw_word in text.read().split()] words_index = set(words) counts_dict = {index:words.count(…
上了一天的课,现在终于可以静下来更新我的博客了.       越来越发现,写博客是一种享受.来看看这次小林老师的“作战任务”.                词频统计 单词: 包含有4个或4个以上的字母 单词由分隔符分开 如果一个字符串包含_非_字母数字,则不是单词 单词大小写不敏感,例如 “file”.“FILE”和“File”可以看作同一个单词 单词必须是字母开头,“file123”是单词,“123file”不是单词                 简单理一下思路:            …