解题思路: 只有尾数为25,50,75,00的数才可能是25的倍数. 对字符串做4次处理,以25为例. a. 将字符串中的最后一个5移到最后一位.计算交换次数.(如果没有找到5,则不可能凑出25,考虑50.75.00) b. 字符串已经改变,将此时最后一个2移到倒数第二位.计算交换次数. (如果没有找到2,则也不可能凑出25,考虑50.75.00) c. 将除了最后两位之外的第一个非0的数字移到首位,计算交换次数.(如果找不到除了最后两位之外的非0数字,则不可能凑出25,考虑50.75.00)…

Divisibility by 25 time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given an integer nn from 11 to 10181018 without leading zeroes. In one move you can swap any two adjacent digits i…

传送门 题意:给定一个数,可以对其做交换相邻两个数字的操作.问最少要操作几步,使得可以被25整除. 思路:问题可以转化为,要做几次交换,使得末尾两个数为00或25,50,75: 自己一开始就是先for一遍,记录四种可能对于的步数,再对四种可能讨论(有前导0的情况):自己是在数据中,该对了自己的代码, 看了队长和%王宣凯的代码,觉得那才是现场能ac的思路.--暴力交换: #include <iostream> #include <cstdio> #include <algori…

Codeforces Round #486 (Div. 3) E. Divisibility by 25 题目连接: http://codeforces.com/group/T0ITBvoeEx/contest/988/problem/E Description You are given an integer n from 1 to 10^18 without leading zeroes. In one move you can swap any two adjacent digits in…

You are given an integer nn from 11 to 10181018 without leading zeroes. In one move you can swap any two adjacent digits in the given number in such a way that the resulting number will not contain leading zeroes. In other words, after each move the…

You are given an integer nn from 11 to 10181018 without leading zeroes. In one move you can swap any two adjacent digits in the given number in such a way that the resulting number will not contain leading zeroes. In other words, after each move the…

遇见模拟题 有两种做法 例如这题: 1.直接去算次数(统计哪个数在第几位,然后去运算) 2.模拟操作 贴一个别人的代码...https://blog.csdn.net/weixin_39453270/article/details/80548780 #include <bits/stdc++.h> using namespace std; const int INF=0x3f3f3f3f; string str1,str2; ; void Get(char a,char b,int n,int…

 Divisibility by Eight time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain…

题目:http://codeforces.com/problemset/problem/597/A Divisibility time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Find the number of k-divisible numbers on the segment [a, b]. In other words y…

J. Divisibility time limit per test 0.5 seconds memory limit per test 64 megabytes input standard input output standard output IT City company developing computer games invented a new way to reward its employees. After a new game release users start…