Codeforces Round #528 (Div. 2)题解 A. Right-Left Cipher 很明显这道题按题意逆序解码即可 Code: # include <bits/stdc++.h> int main() { std::string s, t; std::cin >> s; int len = s.length(); int cnt = 0; for(int i = 0; i < len; i++) { t = t + s[((len + 1) / 2 +…

A. Watching a movie time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have decided to watch the best moments of some movie. There are two buttons on your player: Watch the current minute…

A. Contest time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully sub…

Bakery 题目链接: http://codeforces.com/contest/707/problem/B Description Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities. To bake…

time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Polycarp loves ciphers. He has invented his own cipher called Right-Left. Right-Left cipher is used for strings. To encrypt the string s=s1s2…

A. Right-Left Cipher time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Polycarp loves ciphers. He has invented his own cipher called Right-Left. Right-Left cipher is used for strings. To encr…

A. Right-Left Cipher Solved. 注意长度的奇偶 #include <bits/stdc++.h> using namespace std; string s; int main() { while (cin >> s) { string res = ""; int len = s.size(); ) { cout << s << endl; continue; } int l, r; ) { res += s[s…

传送门:http://codeforces.com/contest/1087/problem/C C. Connect Three time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The Squareland national forest is divided into equal 1×11×1 square plots al…

#include<bits/stdc++.h>using namespace std;char s[200007],t[200007];int last[200007][27],nxt[200007][27];int l[200007],r[200007];int main(){ cin>>s+1>>t+1; int n=strlen(s+1); int m=strlen(t+1); for(int i=1;i<=n;++i){ for(int j=0;j<…

C. Dreamoon and Strings time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Dreamoon has a string s and a pattern string p. He first removes exactly x characters from s obtaining string s' as a…