Binary Operations Time Limit: 2000 ms Memory Limit: 65535 kB Solved: 56 Tried: 674   Description   Bob has a sequence of N integers. They are so attractive, that Alice begs to have a continued part of it(a continued part here also means a continued s…

Binary Number Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1475    Accepted Submission(s): 933 Problem Description For 2 non-negative integers x and y, f(x, y) is defined as the number of dif…

题目描述 The binary weight of a positive  integer is the number of 1's in its binary representation.for example,the decmial number 1 has a binary weight of 1,and the decimal number 1717 (which is 11010110101 in binary) has a binary weight of 7.Give a pos…

题目传送门 题意:所有连续的子序列的三种位运算计算后的值的和的期望分别是多少 分析:因为所有连续子序列的组数有n * (n + 1) / 2种,所以要将他们分类降低复杂度,以ai为结尾的分成一组,至于具体的做法,我觉得这篇题解已经写的很详细了,UESTC 1709 Binary Operations 吐槽一下,题解的代码交上去是TLE的,至今不知道为何,我写的是WA,将所有类型改成ll才AC... /************************************************…

You are given n strings s1, s2, ..., sn consisting of characters 0 and 1. m operations are performed, on each of them you concatenate two existing strings into a new one. On the i-th operation the concatenation saisbi is saved into a new string sn + …

/* PHP中的位运算与位移运算 ＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝ 二进制Binary:0,1 逢二进1,易于电子信号的传输 原码.反码.补码 二进制最高位是符号位:0为正数,1为负数(左边是高位) 原码:二进制表示的数为原码 对于正数:原码反码补码都一样 1 ----> 0000000 00000000 00000000 00000001 对于负数: 反码:原码的符号位不变,其它位取反 补码:对负数的反码+1 -1原码: ---> 10000000 00000000 00000…

C. XOR and OR time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The Bitlandians are quite weird people. They do everything differently. They have a different alphabet so they have a differen…

Problem D. GukiZ and Binary Operations Solution 一位一位考虑,就是求一个二进制序列有连续的1的种类数和没有连续的1的种类数. 没有连续的1的二进制序列的数目满足f[i]=f[i-1]+f[i-2],恰好是斐波那契数列. 数据范围在10^18,用矩阵加速计算,有连续的1的数目就用2^n-f[n+1] 最后枚举k的每一位,是1乘上2^n-f[n+1],是0乘上f[n+1] 注意以上需要满足 2^l>k.并且这里l的最大值为64,需要特判. #inclu…

找球号(三) 时间限制:2000 ms  |  内存限制:3000 KB 难度:2   描述 xiaod现在正在某个球场负责网球的管理工作.为了方便管理,他把每个球都编了号,且每个编号的球的总个数都是偶数.有一天,xiaod发现少了一个球,你能帮他找出丢的那个球的球号吗?   输入 有多组测试数据.每组数据包括两行.第一行是一个整数N(0<N<1000000),表示现在所剩的球数.随后的一行是N个数,表示所剩的各个球的编号M(0<M<10^9). 输出 对于每组数据,输出弄丢的那个…

A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 100000/100000 K (Java/Others) Total Submission(s): 1905    Accepted Submission(s): 668 Problem Description Corrupt governors always find ways to get dirty money…