题目链接 队内赛里,匆匆忙忙写的. #include <cstdio> #include <cstring> #include <iostream> #include <vector> #include <string> #include <map> #include <algorithm> using namespace std; ]; ]; ][]; ]; ]; ]; ][]; ]; ]; ]; int maxz; i…

先分组,然后暴力:注意  初始化时不要为0 会有负数:我直接二进制枚举: dfs是正解:呵呵 #include <iostream> #include <cstdio> #include <cstring> #include <string> #include <vector> #include <map> #include <set> #include <algorithm> using namespace…

不可能解可以直接判断. 搭配产生的附加分可以用一个二维数组保存. 枚举1442,4种类型的人,因为总人数只有23个,所以可以搜索暴力枚举,然后保存最优解. 注意trick,答案可能为负数,所以初始化ans不能为0. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <string>…

Arranging Your Team Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1218    Accepted Submission(s): 360 Problem Description Your country has qualified for the FIFA 2010 South Africa World Cup. A…

HDU 1241 题目大意:给定一块油田,求其连通块的数目.上下左右斜对角相邻的@属于同一个连通块. 解题思路:对每一个@进行dfs遍历并标记访问状态,一次dfs可以访问一个连通块,最后统计数量. /* HDU 1241 Oil Deposits --- 入门DFS */ #include <cstdio> int m, n; //n行m列 ][]; /* 将和i,j同处于一个连通块的字符标记出来 */ void dfs(int i, int j){ || j < || i >=…

HDU 1241  Oil Deposits L -DFS Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u   Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large r…

HDOJ(HDU).1258 Sum It Up (DFS) [从零开始DFS(6)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (DF…

HDOJ(HDU).1016 Prime Ring Problem (DFS) [从零开始DFS(3)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…

思路 题意:此题大意是指首先给你23个队员的信息,包括他们的名字,能力值,在赛场上的职位.然后给出几个若能满足某两个队员同时在球场上就额外加上一定的值.最后让你从23个队员中选出11个人,使得最终的value最大. 具体思路:由于从样例中可以发现字符串比较多,加之需要进行姓名和姓名.score之间关系的记录,这就用到了map.利用dfs对所有队员进行遍历,具体说明在代码中指出. AC代码 //#include<bits/stdc++.h> #include<iostream> #i…

题目链接 Problem Description At Valentine's eve, Shylock and Lucar were enjoying their time as any other couples. Suddenly, LSH, Boss of FFF Group caught both of them, and locked them into two separate cells of the jail randomly. But as the saying goes:…