题目连接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=163 #   Problem Verdict Language Run Time Submission Date 13767338 227 Puzzle Accepted C++ 0.026 2014-06-19 02:39:04 13766276 227 Puzzle Wrong…

A children’s puzzle that was popular years ago consisted of a × frame which contained small squares of equal size. A unique letter of the alphabet was printed on each small square. Since there were only squares within the frame, the frame also contai…

题目: 题目浏览传送门 题意: 给出一个5*5的方格,里边有一个格子是空的,现在给出一串指令,A->空格向上移动,B->空格向下移动,R->空格向右移动,L->空格向左移动. 输出移动后的结果. 思路: 直接上模拟就好了,不过就是输入处理有点恶心,最好用scanf和printf来处理输入输出. 1.空格移动出界和出现不是‘A’.‘B’.‘R’.‘L’中的指令,这两种情况都算是“This puzzle has no final configuration.”. 2.另外在处理指令的时…

#include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> #include <cmath> using namespace std; char maps[5][7]; char cmd[1001]; int main() { int cases = 0; while (gets(maps[0])) {…

之前上传UVa227 puzzle时,好不容易AC了,但发现自己用时50(ms),而在VJ上看到人家都是40ms.20ms,于是打开一个20ms的代码查看人家强在哪里.但结果研究了半天感觉差不多,于是想着应该不是算法的问题.然后又想到,网上提交的答案,大家都是用scanf和printf写的,而我用的cin cout,而这题的确需要大量的输入输出,于是就想着把所有cin cout改成scanf printf.结果 -.- 上面c++版,下面c版. 于是我很好奇C的输入输出方法和C++提倡的方法为什…

各位大佬都好厉害…… 这个ACM/ICPC1993总决赛算黄题%%% 我个人认为至少要绿题. 虽然算法上面不是要求很大 但是操作模拟是真的恶心…… 主要是输入输出的难. 对于ABLR只需要模拟即可 遇到非法指令退出 (输入输出真的很麻烦啊!!) 贴代码 #include<bits/stdc++.h> #define MAXN 5 using namespace std; char grid[MAXN][MAXN]; int blankrow, blankcol, nextrow, nextco…

题目描述:算法竞赛入门经典习题3-5 题目思路:模拟题 #include <stdio.h> #include <string.h> #define maxn 55 char gird[maxn][maxn] ; char cmd[maxn] ; int blank_x,blank_y ; int main(int argc, char *argv[]) { ; ;i<;i++) gets(gird[i]) ; ;i<;i++) ;j<;j++) if(gird[…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 模拟题.. 输入稍微恶心了点. getchar()一个一个搞就好. [代码] #include <bits/stdc++.h> using namespace std; const int N = 5; string s[N + 5],s2; char S[N + 5][N + 5]; int x, y; bool ok() { bool ok = true; for (char key = getchar();key !='…

#include<stdio.h> #include<string.h> char s[5][5]; int main() { while(gets(s[0])) { int t = 0; if(s[0][0] == 'Z') break; int i ,j ,m ,n; for(i = 0;i < 5;i++) { if(i) gets(s[i]); for(j = 0;j < 5;j++) { if(s[i][j] == ' ') { m = i; n = j; b…

书上具体所有题目:http://pan.baidu.com/s/1hssH0KO 题目:算法竞赛入门经典 3-4/UVa455:Periodic Strings 代码: //UVa455 #include<iostream> int main() { char str[82]; int num; std::cin >> num; while (num--) { std::cin>>str; char *ps = str; while (*++ps != '\0') {…

题目链接: https://cn.vjudge.net/problem/UVA-227 /* 问题 输入一个5*5的方格,其中有一些字母填充,还有一个空白位置,输入一连串 的指令,如果指令合法,能够得到一个移动后的方格就输出方格,不能就输出 “This puzzle has no final configuration.” 解题思路 模拟,一个一个的读入字符,包括空格,再读入若干行指令,如果指令表面合法,进入模拟看内容是否合法,不合法直接输出提示. 易错点 读入和控制结束问题,注意读入指令后有一…

题目链接:https://vjudge.net/problem/UVA-227#author=0 题解:这个题不难但需要注意很多点 1.需要输入空格,而cin不读取空格,所以需要getchar,而getchar与NULL联系时,优先级过低,需要加(). 2.每次都需要换行,换行需要getchar() 3.我一开始就报错Runtime error,原因是,最后就算到0到6,越界,也进行运算,那么行数就会变为-1,就越界了,解决办法时加个if #include<iostream>#include&…

Puzzle 面向服务/切面AOP开发框架 For .Net AOP主要实现的目的是针对业务处理过程中的切面进行提取,它所面对的是处理过程中的某个步骤或阶段,以获得逻辑过程中各部分之间低耦合性的隔离效果. 日常的产品开发中最常见的就是数据保存的功能.举例来说,现在有个用户信息数据保存的功能,我们希望在数据保存前对数据进行校验,其中现在能想到的校验就包含数据完整性校验和相同数据是否存在校验.按照传统的OOP(面向对象程序设计),我们需要定义一个IUserDataSaveService(用户数据保存…

步骤:1.把输入的数字和空格保存.(这里用到gets函数读取整行)2.定位空格.3.输入指令. #include<stdio.h> #include<string.h> ][];//声明数组 int main(){ memset(a,,sizeof(a)); ; ; ]; ]; //输入网格 gets(a[]); gets(a[]); gets(a[]); gets(a[]); gets(a[]); //定位空格 ; x<; x++) { ; y<; y++) { if…

题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5456 Description As an exciting puzzle game for kids and girlfriends, the Matches Puzzle Game asks the player to find the number of possible equations A−B=C with exactly n (5≤n≤500) matches (or stic…

one recursive approach to solve hdu 1016, list all permutations, solve N-Queens puzzle. reference: the video of stanford cs106b lecture 10 by Julie Zelenski https://www.youtube.com/watch?v=NdF1QDTRkck // hdu 1016, 795MS #include <cstdio> #include &l…

Katu Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6714   Accepted: 2472 Description Katu Puzzle is presented as a directed graph G(V, E) with each edge e(a, b) labeled by a boolean operator op (one of AND, OR, XOR) and an integ…

Multiplication Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8737   Accepted: 5468 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one…

B. Island Puzzle time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A remote island chain contains n islands, labeled 1 through n. Bidirectional bridges connect the islands to form a simple c…

题目链接:http://poj.org/problem?id=1651 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the prod…

Ignatius's puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4935    Accepted Submission(s): 3359 Problem Description Ignatius is poor at math,he falls across a puzzle problem,so he has no…

A hard puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23766    Accepted Submission(s): 8390 Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and…

Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.this puzzle describes that: gave a and b,how to know…

                                                           M × N Puzzle Time Limit: 4000MS   Memory Limit: 131072K Total Submissions: 4112   Accepted: 1140 Description The Eight Puzzle, among other sliding-tile puzzles, is one of the famous problems…

The Problem. 求解8数码问题.用最少的移动次数能使8数码还原. Best-first search.使用A*算法来解决,我们定义一个Seach Node,它是当前搜索局面的一种状态,记录了从初始到达当前状态的移动次数和上一个状态.初始化时候,当前状态移动次数为0,上一个状态为null,将其放入优先级队列,通过不断的从优先级队列中取出Seach Node去扩展下一级的状态,直到找到目标状态.对于优先级队列中优先级的定义我们可以采用:Hamming priority function 和…

圣诞前上线的App,Tangram Puzzle 限免,大家去下载玩玩. 介绍网站:http://www.mokamisu.com/ App Store:https://itunes.apple.com/en/app/tangram-puzzle/id781360993?mt=8 惯例App的开发总结稍后放出...…

B - Hongcow Solves A Puzzle 题目连接: http://codeforces.com/contest/745/problem/B Description Hongcow likes solving puzzles. One day, Hongcow finds two identical puzzle pieces, with the instructions "make a rectangle" next to them. The pieces can be…

题目大意 构造一条闭合路线,使得路线不能相交,并且走直线的步数小于等于 S,转弯(左转和右转)的步数小于等于 T.(0≤S,T≤1000) 求一条最长的路线 做法分析 注意到,因为要求路线闭合,那么转弯的数量 T 必须大于等于 4,否则无解. 适当 YY 下:只能用偶数个 S 和偶数个 T,不然不可能构成闭合路径.怎么证明,不会... 情况1:S<2 这种情况下,我们不能使用直走的命令,只能通过不断的转弯来实现题目要求的路径,在纸上画了画,大致图形如下: T=4 时:   T=8:没有   T=…

Solve the puzzle, Save the world! Problem Description In the popular TV series Heroes, there is a tagline "Save the cheerleader, Save the world!". Here Heroes continues, "Solve the puzzle, Save the world!".Finally, alien invaders visit…

8.6 Implement a jigsaw puzzle. Design the data structures and explain an algorithm to solve the puzzle. You can assume that you have a f itsWith method which, when passed two puzzle pieces, returns true if the two pieces belong together.…