Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14901   Accepted: 7804 Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c…

1.链接地址: http://bailian.openjudge.cn/practice/2810/ http://bailian.openjudge.cn/practice/1543/ http://poj.org/problem?id=1543 2.题目: Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 13190   Accepted: 6995 Description For hundr…

Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12595   Accepted: 6707 Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c…

Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 15302   Accepted: 7936 Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c…

Problem Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c^n, has remained elusively unproven. (A recent proof is believed to be correct, though it…

zju对时间要求比较高,这就要求我们不能简单地暴力求解(三个循环搞定),就要换个思路:因为在循环时,已知a,确定b,c,d,在外重两层循环中已经给定了b和c,我们就不用遍历d,我们可以利用d^3=a^3-b^3-c^3来判断这个d. 看代码: #include <stdio.h> #include <math.h> int main() { ;n<=;++n) { ],b[],c[],count=,i,flag=; ); ;i<n;i++) { int ai= i*i*…

这道题明显是一道暴力. 暴力枚举每一个 \(a, b, c, d\) 所以我就写了一个暴力.每个 \(a, b, c, d\) 都从 \(1\) 枚举到 \(100\) #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> #define line cout << endl using namespace st…

题号:a001: 哈囉 背景知识:输出语句,while not eof 题号:a002: 簡易加法 背景知识:输出语句,while not eof,加法运算 题号:a003: 兩光法師占卜術 背景知识:while not eof,分支语句,求余 PS:%表示求余 题号:a004: 文文的求婚 背景知识:while not eof,分支语句,判断闰年 题号:a005: Eva 的回家作業 背景知识:循环,if语句,等比数列,等差数列,输出语句 题号:a006: 一元二次方程式 背景知识:if语句的…

acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  1024   Calendar Game       简单题  1027   Human Gene Functions   简单题  1037   Gridland            简单题  1052   Algernon s Noxious Emissions 简单题  1409   Commun…

各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1019 Grandpa's Other Estate 1034 Simple Arithmetics 1036 Complete the sequence! 1043 Maya Calendar 1054 Game Prediction 1057 Mileage Bank 1067 Rails 10…

Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16522   Accepted: 8444 Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c…

2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 1003 Hangover792.762000 1001 Exponentiation752.486000 1006 Biorhythms705.902000 1005 I Think I Need a Houseboat686.540000 1011 Sticks647.566000 1007…

以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…

汇总一些常见的算法题目,参考代码. 注:部分题目没有合适的oj地址 枚举 Perfect Cubes.Biorhythms.Counterfeit Dollar.EXTENDED LIGHTS OUT.特殊密码锁.拨钟问题 递归 nnn的阶乘.汉诺塔问题.N皇后问题.逆波兰表达式.四则运算表达式求值.爬楼梯.放苹果.算24.全排列 二分 二分法求方程的根.和为给定数.Aggressive Cows 分治 输出前k大的数.排列的逆序数 动态规划 The Triangle.最长上升子序列.最长公共子…

本篇博客算是一个开头,接下来会持续更新使用Swift3.0开发服务端相关的博客.当然,我们使用目前使用Swift开发服务端较为成熟的框架Perfect来实现.Perfect框架是加拿大一个创业团队开发的,目前是Perfect2.0版本,关于Perfect框架,下方会详细的介绍.本篇博客会演示一个完整的Demo, 该Demo完全由Swift3.0开发,其中包括服务端和iOS客户端,数据库采用的是MySQL. 进一步说,本篇博客将会演示一个使用Swift3.0开发的记事本,当然该记事本的服务端和iO…

Given a positive integer num, write a function which returns True if num is a perfect square else False. Note: Do not use any built-in library function such as sqrt. Example 1: Input: 16 Returns: True Example 2: Input: 14 Returns: False Credits:Speci…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. Credits:Special thanks…

Link: Rvalue References and Perfect Forwarding in C++0x (https://www.justsoftwaresolutions.co.uk/cplusplus/rvalue_references_and_perfect_forwarding.html) 摘要: std::forward is designed for use in a template function which takes its arguments by T&&,…

Several days ago, I was involved in an argument about choice of C or C++. What I ignored was "language is less important than coder".  a bad C# writer only write shit-like C# but a professional C programmer could design perfect C, Notwithstandin…

Marching Cubes算法是三维离散数据场中提取等值面的经典算法,其主要应用于医学领域的可视化场景,例如CT扫描和MRI扫描的3D重建等. 算法主要的思想是在三维离散数据场中通过线性插值来逼近等值面,具体如下:三维离散数据场中每个栅格单元作为一个体素,体素的每个顶点都存在对应的标量值.如果体素顶点上的值大于或等于等值面值,则定义该顶点位于等值面之外,标记为“0”:而如果体素顶点上的值小于等值面值,则定义该顶点位于等值面之内,标记为“1”.由于每个体素单元有8个顶点,那么共存在2^8 = 2…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 23911   Accepted: 10640 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16 ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 解析: 利用动态规划解决此问题:对于要求的当前节…

题目 Source http://codeforces.com/contest/525/problem/E Description Anya loves to fold and stick. Today she decided to do just that. Anya has n cubes lying in a line and numbered from 1 to n from left to right, with natural numbers written on them. She…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24081   Accepted: 10695 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…

Perfect Scrollbar 是一个很小的,但完美的 jQuery 滚动插件.滚动条不会影响原来的设计布局,滚动条的设计是完全可定制的.你可以改变几乎所有的 CSS 样式的滚动条,滚动条设计对脚本没有依赖性. 您可能感兴趣的相关文章 创意无限!一组网页边栏过渡动画[附源码下载] 真是好东西!13种非常动感的页面加载动画效果 你见过吗?9款超炫的复选框(Checkbox)效果 Magic CSS3 – 帮助你实现神奇的交互动画效果 超赞!基于 Bootstrap 的响应式的后台管理模板 立即…

Given a positive integer num, write a function which returns True if num is a perfect square else False. Note: Do not use any built-in library function such as sqrt. Example 1: Input: 16 Returns: True Example 2: Input: 14 Returns: False 本题可以用binary s…

这道题首先想到的算法是DP.每个perfect square number对应的解都是1.先生成一个n+1长的DP list.对于每个i,可以用dp[i] = min(dp[j] + dp[i-j], dp[i])来更新,这里j 是<= i 的一个perfect square number.但是DP的算法超时. class Solution(object): def numSquares(self, n): """ :type n: int :rtype: int &q…

[codeforces 317]A. Perfect Pair 试题描述 Let us call a pair of integer numbers m-perfect, if at least one number in the pair is greater than or equal to m. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not. Two integers x, y a…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. ExampleGiven n = 12, return 3 because 12 = 4 + 4 + 4Given n = 13, return 2 because 13 = 4 + 9 LeetCode上的原题,请参见我之前的博客Perfect Sq…

Given a positive integer n, find the least number of perfect square numbers (for example,1, 4, 9, 16, ...) which sum to n. Given n = 12, return 3 because 12 = 4 + 4 + 4Given n = 13, return 2 because 13 = 4 + 9 刷这道题目发现网上有四种解法 http://www.cnblogs.com/gr…