A1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a po…

第五天 A1009 Product of Polynomials (25 分) 题目内容 This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, wh…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

课本AC代码 #include <cstdio> struct Poly { int exp;//指数 double cof; } poly[1001];//第一个多项式 double ans[2001];//存放结果 int main() { #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE int n, m, number = 0; scanf…

两个多项式的乘积 两个数组,一个放多项式1,一个放结果 注意:arr2[j+exp]+=arr1[j]*coe; 因为有指数相加相同的情况下需要合并系数 #include<cstdio> int main(){ ]={]={0.0},coe; ,n,m; scanf("%d", &n); ;i<n;i++){ scanf("%d%lf",&exp,&coe); arr1[exp]=coe; } scanf("%d&…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

B1018. 锤子剪刀布 (20) Discription: 大家应该都会玩"锤子剪刀布"的游戏:两人同时给出手势,胜负规则如图所示: 现给出两人的交锋记录,请统计双方的胜.平.负次数,并且给出双方分别出什么手势的胜算最大. Input: 输入第1行给出正整数N(<=105),即双方交锋的次数.随后N行,每行给出一次交锋的信息,即甲.乙双方同时给出的的手势.C代表"锤子".J代表"剪刀".B代表"布",第1个字母代表甲方…

SQL> select * from (select * from t1 order by id ) where rownum<20; ID A1 A2 A3 ---------- ---------- ---------- ---------- 1 1 1 a1 10 10 10 a10 100 100 100 a100 1000 1000 1000 a1000 10000 10000 10000 a10000 1001 1001 1001 a1001 1002 1002 1002 a100…

<pre name="code" class="html">SQL> select * from t1 where id>=1 and id<=20; ID A1 A2 A3 ---------- ---------- ---------- ---------- 1 1 1 a1 2 2 2 a2 3 3 3 a3 4 4 4 a4 5 5 5 a5 6 6 6 a6 7 7 7 a7 8 8 8 a8 9 9 9 a9 10 10 1…