XTU 1242 Yada Number 容斥】的更多相关文章

Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,11,13 in its prime factors is even. For instance, 18=2 * 3 * 3 is no…
Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,11,13 in its prime factors is even. For instance, 18=2 * 3 * 3 is no…
Yada Number       Time Limit : 2000 MS   Memory Limit : 65536 KB   Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,1…
至今觉得这场 edu 的 G 比 EF 都要简单-- 不知道为什么出题人要把 \(m=0\) 放进去,先特判掉. 要求至少一个 \(0\),至少一个 \(1\),至少一个 \(2\),容斥一波,变成总方案数-没有 \(0\)-没有 \(1\)-没有 \(2\)+没有 \(01\)+没有 \(02\)+没有 \(12\)+没有 \(012\). 没有 \(0\) 和没有 \(2\) 比较难搞,放到最后讨论. 没有 \(1\),考虑一个联通块,这个联通块所有数都一样,方案数是 \(2^{cnt}\)…
题意:https://codeforc.es/contest/1207/problem/D n个元素,每个元素有a.b两个属性,问你n个元素的a序列和b序列有多少种排序方法使他们不同时非递减(不同时good). 思路: 真难则反+容斥,反向考虑,ans1=如果a序列非递减则有a中各个数字出现次数的阶乘的乘积个,ans2=b序列也是一样. ans3=然后还要减去a序列和b序列都是good的方案数,就是元素相同的出现次数阶乘的乘积(注意,如果不存在双good就不算ans3). ANS就是:全排列 -…
C. Mike and Foam time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Mike is a bartender at Rico's bar. At Rico's, they put beer glasses in a special shelf. There are n kinds of beer at Rico's…
题目 Source http://acm.hust.edu.cn/vjudge/problem/42145 Description Let’s assume there is a new chess piece named Super-rook. When placed at a cell of a chessboard, it attacks all the cells that belong to the same row or same column. Additionally it at…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4249    Accepted Submission(s): 1211 Problem Description   Now you get a number N, and a M-integers set, you shoul…
GCD 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=1695 Description Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y) = k. GCD(x, y) means the greatest common divisor of x and y. Since the number of choices may be…
A Simple Chess 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5794 Description There is a n×m board, a chess want to go to the position (n,m) from the position (1,1). The chess is able to go to position (x2,y2) from the position (x1,y1), only and if…