Revenge of Nim hdu 4994 (博弈)】的更多相关文章

http://acm.split.hdu.edu.cn/showproblem.php?pid=4994 题意:现在有两个人在取石子,共有n堆石子,每堆石子取完后才可以取下一堆石子,最后一个取石子的人胜利输出'Yes',否则输出'No' 分析:要想看最后一堆石子是谁取走的,我们则需要判断在前n-1堆石子中,主动权在谁的手上.试想,除了在迫不得已的情况下(a[i]==1)不得不这么取,两个人都可以通过取(1-a[i])不等的石子来确保自己手里的主动权.倘若在遇到比1大的数字时,只需要判断在这个数字…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4994 题目意思:有 n 个 heap(假设从左至右编号为1-n),每个 heap 上有一些 objects.有两个player,轮流从左至右的 heap 上取走 object(1 <= 取走数 <= 当前heap上的最多objects数),规定当前的 heapi 如果还有object,那么不能取走heapi+1的object,直到把 heapi 的 object 全部取光. 题解在这里 http:…
F - 6 Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4994 Description Nim is a mathematical game of strategy in which two players take turns removing objects from distinct heaps. On each turn,…
Revenge of Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 562    Accepted Submission(s): 290 Problem Description Nim is a mathematical game of strategy in which two players take turns remov…
Revenge of Nim II Problem DescriptionNim is a mathematical game of strategy in which two players take turns removing objects from distinct heaps. On each turn, a player must remove at least one object, and may remove any number of objects provided th…
位运算.. .. Revenge of Nim II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 229    Accepted Submission(s): 79 Problem Description Nim is a mathematical game of strategy in which two players take…
S-Nim HDU 1536 博弈 sg函数 题意 首先输入K,表示一个集合的大小,之后输入集合,表示对于这对石子只能去这个集合中的元素的个数,之后输入 一个m表示接下来对于这个集合要进行m次询问,之后m行,每行输入一个n表示有n个堆,每堆有n1个石子,问这一行所表示的状态是赢还是输,如果赢输入W否则L. 解题思路 如果没有每次取石子个数的限制的话,那么仅仅需要把每堆石子的个数进行异或运算即可,如果结果不是1,那么先手赢,反之后手赢. 但是这里对每次取石子的个数进行了限制,每次只能从几个数中进行…
Problem Description Nim is a mathematical game of strategy in which two players take turns removing objects from distinct heaps. On each turn, a player must remove at least one object, and may remove any number of objects provided they all come from…
http://acm.hdu.edu.cn/showproblem.php?pid=4994 Nim游戏变成从前往后有序的,谁是winner? 如果当前堆数目为1,玩家没有选择,只能取走.遇到到不为1的堆,则当前回合行动者可以选择下次选择的先后手.考虑之后的状态为S,如果S为必败态,则玩家可以取完当前堆,下轮变后手,否则,将当前堆数目变为1,下轮先手. #include <cstdio> #include <cstdlib> #include <cmath> #incl…
Nim or not Nim? Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3032 Description Nim is a two-player mathematic game of strategy in which players take turns removing objects from distinct heaps.…