Wolf and Rabbit Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9060    Accepted Submission(s): 4612 Problem Description There is a hill with n holes around. The holes are signed from 0 to n-1.…

一个很坑的问题,想到点子上很好解决,想不到的话头破也不一定能做出来. There is a hill with n holes around. The holes are signed from 0 to n-1. A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0…

#include<cstdio> #include<string> #include<cstdlib> #include<cmath> #include<iostream> #include<cstring> #include<set> #include<queue> #include<algorithm> #include<vector> #include<map> #in…

You are given positive integer number n. You should create such strictly increasingsequence of k positive numbers a1, a2, ..., ak, that their sum is equal to n and greatest common divisor is maximal. Greatest common divisor of sequence is maximum of…

题意:在\(1\)~\(n\)中找两个不相等的数使得他们的\(gcd\)最大. 题解:水题,如果\(n\)是偶数,那么一定取\(n\)和\(n/2\),\(n\)是奇数的话,取\(n-1\)和\((n-1)/2\). 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <stac…

Wolf and Rabbit Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5922    Accepted Submission(s): 2972点我 Problem Description There is a hill with n holes around. The holes are signed from 0 to n-1…

HDU 1222   Wolf and Rabbit   (最大公约数)解题报告 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88159#problem/G 题目: Description There is a hill with n holes around. The holes are signed from 0 to n-1.        A rabbit must hide in one of the holes…

Problem Description There is a hill with n holes around. The holes are signed from 0 to n-1. A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0. Then he will…

C. Maximal GCD time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given positive integer number n. You should create such strictly increasing sequence of k positive numbers a1, a2, ...…

1.gcd 递归实现 int gcd(int i,int j){ if(j==0) return i; else return gcd(j,i%j);} 2.lcm int gcd(int i,int j){if(j==0) return i;else return gcd(j,i%j);} int lcm(int i ,int j) { return i*j/gcd(i*j); } 3. E - Wolf and Rabbit 兔子坑问题 There is a hill with n hole…