2024 BUPT Programming Contest F】的更多相关文章

F. Contestants Ranking time limit per test:1 second memory limit per test:24 megabytes input:standard input output:standard output Ahmad is one of the best students in HIAST, and also a very good problems Solver. In the time you will spend reading th…
F. Two Points time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are two points (x1, y1) and (x2, y2) on the plane. They move with the velocities (vx1, vy1) and (vx2, vy2). Find the min…
题目:https://codeforces.com/gym/101908/problem/F 题意:给你n个舞台,每个舞台有很多个节目,每个节目有个开始时间,结束时间,价值,每个舞台至少出演过一个节目,所有舞台同一时刻只能一个舞台演节目,求怎么安排节目有最大价值 思路:首先舞台数只有10,而且我们必须访问每个舞台至少一次,很明显是个状态   1<<10 ,分别代表每个舞台现在演过节目没有,然后很明显我们还有有一个区间状态. 如果题目没有要求每个舞台必须演一次的话,很明显这个问题我们就可以直接按…
题意:给你一个长度为$n$的数组,定义函数$f(l,r)=a_{l} \oplus a_{l+1} \oplus...\oplus a_{r}$,$F(l,r)=f(l,l)\oplus f(l,l+1)\oplus ...\oplus f(l,r)\oplus f(l+1,l+1)\oplus ...f(l+1,r)\oplus ...\oplus f(r,r)$,有两种操作,第一种将数组中某个元素$a[x]$变为$y$,第二种计算$F(l,r)$的值. 思路:打表后发现只有当$l$和$r$同…
#include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ull unsigned l…
Problem F Funny Car Racing There is a funny car racing in a city with n junctions and m directed roads. The funny part is: each road is open and closed periodically. Each road is associate with two integers (a, b), that means the road will be open fo…
[AtCoder] NIKKEI Programming Contest 2019   本来看见这一场的排名的画风比较正常就来补一下题,但是完全没有发现后两题的AC人数远少于我补的上一份AtCoder. A - Subscribers   首先始终 \(max = \min(A, B)\) ,\(min\) 的话如果 \(A + B \leq N\) ,那么就是 \(0\) ,否则就是 \(A + B - N\) . int n, a, b; int main() { read(n), read…
http://acm.zju.edu.cn/onlinejudge/showContestProblem.do?problemId=5503 The 12th Zhejiang Provincial Collegiate Programming Contest - K Capture the Flag Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge In computer security, Capture…
http://acm.zju.edu.cn/onlinejudge/showContestProblem.do?problemId=5502  The 12th Zhejiang Provincial Collegiate Programming Contest - J Convert QWERTY to Dvorak Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward, a poor copy typist, is a user o…
2016 Sichuan Province Programming Contest 代码 2016 Sichuan Province Programming Contest A. Nearest Neighbor Search \(dx\)根据\(x_0\)与\([x_1, x_2]\)位置考虑. \(dx.dy.dz\)单独考虑. B. Odd Discount 做法一:对于两个不同优惠\((i,j)\),所有方案中与两个优惠商品交集为奇数,即同时取到两种优惠的个数为\(2^{n-2}\)种.…