LeetCode 876 Middle of the Linked List 解题报告

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LeetCode 876 Middle of the Linked List 解题报告

题目要求 Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. 题目分析及思路题目给出一个非空单链表,要求返回链表单的中间结点.可以将链表中的结点保存在list中,直接获取中间结点的索引即可. python代码 # Definition…

【LeetCode】876. Middle of the Linked List 解题报告（Python）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法使用哑结点不使用哑结点日期题目地址:https://leetcode.com/problems/middle-of-the-linked-list/description/ 题目描述 Given a non-empty, singly linked list with head node head, return a middle node o…

[LeetCode] 876. Middle of the Linked List 链表的中间结点

Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example 1: Input: [1,2,3,4,5] Output: Node 3 from this list (Serialization: [3,4,5]) The ret…

[LeetCode] 876. Middle of the Linked List_Easy tag: Linked List ** slow, fast pointers

Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example 1: Input: [1,2,3,4,5] Output: Node 3 from this list (Serialization: [3,4,5]) The ret…

LeetCode 876. Middle of the Linked List（获得链表中心结点）

题意:获得链表中心结点.当有两个中心结点时,返回第二个. 分析:快慢指针. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* middleNode(ListNode* head) { if(head…

【LeetCode】328. Odd Even Linked List 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法日期题目地址:https://leetcode.com/problems/odd-even-linked-list/description/ 题目描述 Given a singly linked list, group all odd nodes together followed by the even nodes. Please note he…

Leetcode:Flatten Binary Tree to Linked List 解题报告

Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 SOLUTION 1:使用递归解决,根据left是否为空,先连接left tree, 然后再连接右子树.使用一个t…