一.技术总结 最开始的想法是直接用一个vector容器,装下所有的元素,然后再使用sort()函数排序一下,再取出中值,岂不完美可是失败了,不知道是容器问题还是什么问题,就是编译没有报错,最后总是感觉不对,在PAT测试点也显示段错误.最后看别人的办法了.大部分是先判断出来中值的位置,然后存储两个数组,最后进行比较,当出现了小于median值的位置的时候那么就可以输出该数了. 二.参考代码 #include<iostream> #include<algorithm> using na…

1029 Median (25 分)   Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequen…

1029 Median (25 分)   Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequen…

Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to be…

题目 Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to…

题意: 输入一个正整数N(<=2e5),接着输入N个非递减序的长整数. 输入一个正整数N(<=2e5),接着输入N个非递减序的长整数.(重复一次) 输出两组数合并后的中位数.(200ms,合并后排序会超时,利用两组数是有序的进行模拟) AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ int n; cin>>…

06-图1 列出连通集   (25分) 给定一个有NN个顶点和EE条边的无向图,请用DFS和BFS分别列出其所有的连通集.假设顶点从0到N-1N−1编号.进行搜索时,假设我们总是从编号最小的顶点出发,按编号递增的顺序访问邻接点. 输入格式: 输入第1行给出2个整数NN(0<N\le 100<N≤10)和EE,分别是图的顶点数和边数.随后EE行,每行给出一条边的两个端点.每行中的数字之间用1空格分隔. 输出格式: 按照"{ v_1v​1​​ v_2v​2​​ ... v_kv​k​​ …

(一)题目 题目链接:https://www.patest.cn/contests/pat-a-practise/1029 1029. Median (25) Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1={11, 12, 13, 14} is 12, and the median of S2=…

01-复杂度2 Maximum Subsequence Sum   (25分) Given a sequence of K integers { N​1​​,N​2​​, ..., N​K​​ }. A continuous subsequence is defined to be { N​i​​,N​i+1​​, ..., N​j​​ } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has…

7-17 字符串关键字的散列映射(25 分) 给定一系列由大写英文字母组成的字符串关键字和素数P,用移位法定义的散列函数H(Key)将关键字Key中的最后3个字符映射为整数,每个字符占5位:再用除留余数法将整数映射到长度为P的散列表中.例如将字符串AZDEG插入长度为1009的散列表中,我们首先将26个大写英文字母顺序映射到整数0~25:再通过移位将其映射为3×32​2​​+4×32+6=3206:然后根据表长得到,即是该字符串的散列映射位置. 发生冲突时请用平方探测法解决. 输入格式: 输入第…