zoj2412 dfs连通图】的更多相关文章

zoj2412 #include<stdio.h> #include<iostream> #include<cstdio> #include<queue> #include<cmath> #include<cstring> #include<cstdlib> #include<climits> #include<algorithm> using namespace std; #define ll l…
Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a different type of pipe. There are 11 types of pipes, which is marked…
Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It…
Description Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer…
我是按照这里的思路来的.这个博文只是感性理解. 递归树 关于递归树,这篇博文讲的很好,我只是给自己总结一下. 定义vis数组,在dfs连通图时赋予它们不同的含义: vis=0,表示这个点没有被访问. vis=1,表示这个点被访问了,但是它的孩子还没有访问完. vis=2,表示这个点被访问了,并且它的孩子访问完了. 一个连通图,一定可以表示成一个递归树,加上一些边.这些边的种类有: 树边,也就是递归树上的边.表现为访问(u, v)时,\(vis[v]=0\). 回边,是一个点连向它递归树上的祖宗的…
在图论中,连通图基于连通的概念.在一个无向图 G 中,若从顶点vi到顶点vj有路径相连(当然从vj到vi也一定有路径),则称vi和vj是连通的.如果 G 是有向图,那么连接vi和vj的路径中所有的边都必须同向.如果图中任意两点都是连通的,那么图被称作连通图.如果此图是有向图,则称为强连通图(注意:需要双向都有路径).图的连通性是图的基本性质.   严格定义(摘抄): 对一个图 G=(V,E) 中的两点 x 和 y ,若存在交替的顶点和边的序列 Γ=(x=v0-e1-v1-e2-...-ek-(v…
It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other highways to keep the rest of…
/*该题被博客里标记为中等题,30分钟内1A,掌握了算法就简单了,单向连通图判定,单向连通图缩点 后必然唯一存在出度为0的点和入度为0的点,并且从入度为0的点出发,可以遍历所有点后到达出度为0点 (一条长链),(容易反证),所以缩点后,我重新建图(以前觉得重新建图好麻烦,现在看来SO easy), ,对新有向无环图,从入度为0的点做dfs(回溯时要标记回来,因为要所有dfs路线),有一条深度到达 强连通分支数即为yes,反之no*/ #include<iostream> //297MS, 1A…
//采用邻接矩阵表示图的深度优先搜索遍历(与深度优先搜索遍历连通图的递归算法仅仅是DFS的遍历方式变了) #include <iostream> using namespace std; #define MVNun 100 typedef char VerTexType; typedef int ArcType; typedef struct { VerTexType vexs[MVNun]; ArcType arcs[MVNun][MVNun]; int vexnum, arcnum; }G…
以下面一个题目为例,[题目链接]: https://www.luogu.com.cn/problem/P4961 题目中涉及求出八联通图的个数,这里给出这步的代码: memset(vis, 0, sizeof(vis)); int cnt = 0; for(int i = 0; i < n; i++) { for(int j = 0; j < m; j++) { if(!bomb[i][j] && !vis[i][j]) { ++cnt; vis[i][j] = 1; dfs(…