class Solution { public: char *strStr(char *haystack, char *needle) { if (haystack == NULL || needle == NULL) return NULL; ]; ; ; ; i < ; i++) wpos[i] = -; ; (cur = needle[i]) != '\0'; i++, len++) wpos[cur] = i; , q = ; while (true) { while (haystack…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Update (2014-11-02): The signature of the function had been updated to return the index instead of the pointer. If you still…

利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectangle-in-histo…

利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectangle-in-histo…

原链接:http://blog.csdn.net/yangliuy/article/details/44514495 注:此分类仅供大概参考,没有精雕细琢.有不同意见欢迎评论~ 利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 28: Implement strStr()https://oj.leetcode.com/problems/implement-strstr/ Implement strStr().Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of h…

题目来源: https://leetcode.com/problems/implement-strstr/ 题意分析: 输入两个字符串haystack和needle,如果needle是haystack的一个子串,那么返回这个子串在haystack出现的第一个位置,否则返回-1. 题目思路: 这个题目是简单题,直接暴力解决就可以了.从i=0出发,如果遇到haystack[i] == needle[0],那么判断从这个出发能不能构成needle,如果可以则返回i.直到i到最后一个字符的长度小于nee…

LeetCode 题目总结/分类 利用堆栈: http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/ http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心) http://oj.leetcode.com/problems/valid-parentheses/ http://oj.leetcode.com/problems/large…

Leetcode Solutions Language: javascript c mysql Last updated: 2019-01-04 https://github.com/nusr/leetcode # Problems Solutions Difficulty Acceptance Paid-Only 001 two-sum c,javascript Easy 39.69% No 002 add-two-numbers javascript Medium 30.01% No 007…

题目链接: https://leetcode.com/problems/implement-strstr/?tab=Description   Problem : 实现找子串的操作:如果没有找到则返回-1  ,如果找到则返回第一个匹配位置第一个字符的下标   遍历操作,依次遍历子串中的元素,从长串的第i个元素位置开始,当成功遍历结束子串所有元素时,返回此时的i即时所求结果, 如果此时的i+j已经等于长串的个数,那么表示没有找到,返回-1    参考代码: package leetcode_50;…