Dylans loves tree Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1444 Accepted Submission(s): 329 Problem Description Dylans is given a tree with N nodes. All nodes have a value A[i].Nodes…
题目链接:pid=3631" style="font-size:18px">http://acm.hdu.edu.cn/showproblem.php?pid=3631 Shortest Path Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3962 Accepted Submission(s): 9…
Description Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the path connecting the source vertex to the target vertex. And if two path is said to be non-overlapping, it means that the tw…
Shortest Path 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5636 Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1 to n and there is an edge with unit length between i and i+1 (1≤i<n). To make the graph more in…
Shortest Path Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1146 Accepted Submission(s): 358 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1 to…
Shortest Path Time Limit: 1000MS Memory Limit: 32768KB 64bit IO Format: %I64d & %I64u SubmitStatus Description When YY was a boy and LMY was a girl, they trained for NOI (National Olympiad in Informatics) in GD team. One day, GD team's coach, Prof. G…
The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que camb…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5636 题解: 1.暴力枚举: #include<cmath> #include<cstdio> #include<iostream> #include<algorithm> using namespace std; typedef long long LL; ; ; int n, m; ], b[]; int main() { int T; scanf(&qu…
题目链接 HDU5636 n个点,其中编号相邻的两个点之间都有一条长度为1的边,然后除此之外还有3条长度为1的边. m个询问,每次询问求两个点之前的最短路. 我们把这三条边的6个点两两算最短路, 然后询问的时候用这6个点的距离来更新答案就可以了. (不过听说好像有更好的方法,先占个坑) 时间复杂度$O(216m)$ #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i <=…
The LCIS on the Tree Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 175 Accepted Submission(s): 40 Problem Description For a sequence S1, S2, ... , SN, and a pair of integers (i, j), if 1 <=…
Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on. The Nya graph is an undirect…
This world need more Zhu 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5840 Description As we all know, Zhu is the most powerful man. He has the infinite power to protest the world. We need more men like Zhu! In Duoladuo, this place is like a tree.…
D. Happy Tree Party Bogdan has a birthday today and mom gave him a tree consisting of n vertecies. For every edge of the tree i, some number xi was written on it. In case you forget, a tree is a connected non-directed graph without cycles. After…
pid=5647">[HDU 5647]DZY Loves Connecting(树DP) DZY Loves Connecting Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 332 Accepted Submission(s): 112 Problem Description DZY has an unroote…
Multiply game Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3224 Accepted Submission(s): 1173 Problem Description Tired of playing computer games, alpc23 is planning to play a game on numbe…
HDU - 4725 The Shortest Path in Nya Graph http://acm.hdu.edu.cn/showproblem.php?pid=4725 This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not und…
Necklace HDU - 3874 Mery has a beautiful necklace. The necklace is made up of N magic balls. Each ball has a beautiful value. The balls with the same beautiful value look the same, so if two or more balls have the same beautiful value, we just count…
