http://poj.org/problem?id=2192 Zipper Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 17585   Accepted: 6253 Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the…

  Zipper Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8072    Accepted Submission(s): 2843 Problem Description Given three strings, you are to determine whether the third string can be formed…

Zipper Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4884    Accepted Submission(s): 1742 Problem Description Given three strings, you are to determine whether the third string can be formed…

意甲冠军  是否可以由串来推断a,b字符不改变其相对为了获取字符串的组合c 本题有两种解法  DP或者DFS 考虑DP  令d[i][j]表示是否能有a的前i个字符和b的前j个字符组合得到c的前i+j个字符  值为0或者1  那么有d[i][j]=(d[i-1][j]&&a[i]==c[i+j])||(d[i][j-1]&&b[i]==c[i+j])   a,b的下标都是从1開始的  注意0的初始化 #include<cstdio> #include<cs…

Zipper Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 59   Accepted Submission(s) : 26 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Given three strings, you are t…

Zipper Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15277   Accepted: 5393 Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first tw…

ListZipper 模块 $ cabal install ListZipper Installed ListZipper-1.2.0.2 Prelude> :m +Data.List.Zipper Prelude Data.List.Zipper> Zipper 和 ListZipper Zipper 是一种带焦点(focus,也称游标, cursor)的数据结构.使用 Zipper 可以很方便的在底层数据结构中进行遍历,更新,插入,删除等操作. ListZipper 是建立在 List 这…

Zipper Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order…

1010. Zipper Constraints Time Limit: 1 secs, Memory Limit: 32 MB Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arb…

HDU 1501 Zipper [DFS+剪枝] Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in…