翻转整数 Reverse digits of a number】的更多相关文章

两种方法翻转一个整数.顺序翻转和递归翻转 这里没考虑overflow的情况 递归的作用是使得反向处理.即从递归栈的最低端開始处理.通过绘图可得. 假设是rec(num/10): 12345 1234 123 12 1         <-- 递归使得这个最先处理 package recursion; public class Reverse_digits_of_a_number { public static void main(String[] args) { int num = 123; S…
Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throu…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only hold integers within t…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only store integers within…
Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview?     Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integ…
Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alread…
Reverse Integer Reverse digits of an integer. Example1: x =  123, return  321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alr…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only store integers within…
Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer's…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pairs in the given array. Example1: Input: [1,3,2,3,1] Output: 2  Example2: Input: [2,4,3,5,1] Output:…
给定一个 32 位有符号整数,将整数中的数字进行反转. 示例 1: 输入: 123 输出: 321  示例 2: 输入: -123 输出: -321 示例 3: 输入: 120 输出: 21 注意: 假设我们的环境只能存储 32 位有符号整数,其数值范围是 [−231,  231 − 1].根据这个假设,如果反转后的整数溢出,则返回 0. ===============================================================================…
[抄题]: 给你一个链表以及一个k,将这个链表从头指针开始每k个翻转一下.链表元素个数不是k的倍数,最后剩余的不用翻转. [思维问题]: [一句话思路]: // reverse head->n1->..->nk->next.. // to head->nk->..->n1->next.. // return n1 每k个转一次,再递归 [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): [画图]: [一刷]: h…
全部 [抄题]: Reverse a singly linked list. [思维问题]: 以为要用dummy node [一句话思路]: 直接全部转过来就行了,用dummy node反而多余 [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): [画图]: [一刷]: return curt错了,应该是prev [总结]: 完全转过来之后,最早的prev应该是null [复杂度]:Time complexity: O(1) Space comple…
列表的定义: 列表的使用以及取值:用逗号的方式,取列表两个值,会打印出2个项目,两个项目之间自动有一个空格. 如果想取中间几个值: 请注意,如果取值1和2,那么要写[1,3],要记住这里是顾头不顾尾. 以上的动作就叫切片. 如果想取最后一个数值: 如果想取倒数第二个,可以这么取: 如果想取最后2个数值: 下面截图的写法是错误的,只能得到空值 请注意取值是从左往右取的,所以必须先写-3来取最后2个数值.但是实际这种写法也是错误的,因为顾头不顾尾,会造成如下结果: 变成是取最后倒数第2和倒数第3的数…
数学题 172. Factorial Trailing Zeroes Given an integer n, return the number of trailing zeroes in n!. Note: Your solution should be in logarithmic time complexity. (Easy) 分析:求n的阶乘中末位0的个数,也就是求n!中因数5的个数(2比5多),简单思路是遍历一遍,对于每个数,以此除以5求其因数5的个数,但会超时. 考虑到一个数n比他小…
class Solution { public: int reverse(int x) { ;//long 是怕中间过程溢出 <<,max=-min-){ ans=ans*+x%; x=x/; } if(ans>max||ans<min) ; return ans; } }; 注释: 这是进制转换问题. 转化过程中一定要考虑溢出. 清楚各种类型的表示范围. 附 32位平台: unsigned   int   0-4294967295   int    -2147483648-214…
知识点: 内置变量 INT_MAX   INT_MIN 运算结果是否溢出的判断 判断pop>7即pop>INT_MAX%10 判断pop<-8即pop<INT_MIN%10 class Solution { public: int reverse(int x) { ; while(x) { pop = x%; x /= ; || (ans == INT_MAX/ && pop >)) ; || (ans == INT_MIN/ && pop &…
Given a 32-bit signed integer, reverse digits of an integer. 将32位整数反向输出. Note:Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 题意: 给定一个10进制整数,翻转它. Solution1: directly do the simulation. Two tricky parts to be hand…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could only store integers within…
题目 Given a 32-bit signed integer, reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123,return -321 Example3: x = 120, return 21 思路 问题的关键在于对溢出的判断. 思路1:用long或者long long 直接用long或者long long计算,这样就保证不会溢出,再判断反转后的数字是否溢出. 思路2:stoi()…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:整数,反转,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 转成字符串 数学 日期 题目地址:https://leetcode.com/problems/reverse-integer/description/ 题目描述 Given a 32-bit signed integer, reverse d…
问题: Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return –321   Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the in…
Question:Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the…
[Q7]  把数倒过来 Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Solution: https://leetcode.com/problems/reverse-integer/discuss/229800/Pyt…
Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…
题目等级:Easy 题目描述: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21    题意:给出一个 32 位的有符号整数,你需要将这个整数中每位上的数字进行反转. 解题思路:   本题很简单,我们给出以下两种方法.  …
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3838 访问. 给定一个 32 位有符号整数,将整数中的数字进行反转. 输入: 123 输出: 321 输入: -123 输出: -321 输入: 120 输出: 21 注意: 假设我们的环境只能存储 32 位有符号整数,其数值范围是 [−231,  231 − 1].根据这个假设,如果反转后的整数溢出,则返回 0. Given a 32-bit signed i…