Codeforces Round #303 (Div. 2) C dp 贪心】的更多相关文章

C. Woodcutters time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immedi…
C. Woodcutters Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/545/problem/C Description Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately s…
题目链接:http://codeforces.com/problemset/problem/545/D 题解: 问经过调整,最多能使多少个人满意. 首先是排序,然后策略是:如果这个人对等待时间满意,则将其加入队伍中,更新当前的等候时间:如果不满意,既然等待时间最小了都不满意,那把他扔到最后,即跳过他,接着考虑下一个. 代码如下: #include<cstdio>//F - F CodeForces - 545D #include<cstring> #include<cstdl…
B. Equidistant String time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her string…
题目传送门 /* 题意:每棵树给出坐标和高度,可以往左右倒,也可以不倒 问最多能砍到多少棵树 DP:dp[i][0/1/2] 表示到了第i棵树时,它倒左或右或不动能倒多少棵树 分情况讨论,若符合就取最大值更新,线性dp,自己做出来了:) */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostream> using na…
题目传送门 /* 题意:找到一个字符串p,使得它和s,t的不同的总个数相同 贪心:假设p与s相同,奇偶变换赋值,当是偶数,则有答案 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostream> using namespace std; ; const int INF = 0x3f3f3f3f; int p[MAXN…
题目传送门 /* 比C还水... */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostream> using namespace std; typedef long long ll; ; const int INF = 0x3f3f3f3f; ll a[MAXN]; int main(void) //Codeforc…
题目传送门 /* 题意:5种情况对应对应第i或j辆车翻了没 水题:其实就看对角线的上半边就可以了,vis判断,可惜WA了一次 3: if both cars turned over during the collision. 是指i,j两辆车,而不是全部 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostream>…
题目链接: http://codeforces.com/problemset/problem/268/E E. Playlist time limit per test 1 secondmemory limit per test 256 megabytes 问题描述 Manao's friends often send him new songs. He never listens to them right away. Instead, he compiles them into a play…
https://codeforces.com/contest/1256 A:Payment Without Change[思维] 题意:给你a个价值n的物品和b个价值1的物品,问是否存在取物方案使得价值为s 题解:min(s/n,a)*n+b>=s?YES:NO #include<iostream> #include<cstdio> #include<cstdlib> #include<cmath> #include<algorithm>…